Question

The diameter of the tungsten wire in a lightbulb filament is very small, less than two thousandths of an inch, or about 1/20 mm. The mass of the filament is so very small - 0.0176 grams - that it would take 1600 filaments to weigh an ounce! How many tungsten Atoms are in a typical lightbulb filament?

Answer 1

Answer:

5.76x10¹⁹ atoms

Explanation:

In this case, we have the mass of the tungsten which is 0.0176 g, to get the atoms of the filament of tungsten, we need to use the avogadro number which is:

N° = 6.02x10²³

This number is relationed with the number of moles of any atom or molecule. So to get the atoms of the tungsten, we need to get the number of moles of the tungsten. This can be done using the molecular weight of tungsten which is 183.84 g/mol:

n = 0.0176 / 183.84

n = 9.57x10⁻⁵ moles

Now that we have the moles, we can use the avogadro number to get the atoms:

If: 1 mol = 6.02x10²³ atoms, then 9.57x10⁻⁵ are:

n° atoms = 9.57x10⁻⁵ * 6.02x10²³

n° atoms = 5.76x10¹⁹ atoms of tungsten

Answer 2

The number of tungsten Atoms in a typical light bulb filament is

5.76 × $10^{19}$  atoms of W

Explanation:

Write the given values of the problem

The diameter the tungsten wire in a light bulb filament Tungsten element W : molar mass = 183.84 g / mol

0.0176 g W ×  $\frac{1mol}{183.84 g}$ = 0.000096 mol W

0.000096 mol W ×  $\frac{6.02 × [tex]10^{23 atoms}$}{1 mol W}[/tex]

= 5.76 × $10^{19}$ atoms of W