1) Analysis subquestions (7 points): (a) Draw the mechanism of the reaction - remember, there are two main parts to the aldol co
ndensation, the addition step, followed by the elimination. (b) Explain why your reaction forms the enone product, rather than the hydroxyketone intermediate. 2) Critical analysis (7 points): a) You have been given a 1H NMR spectrum of your product. Fully assign this spectrum (i.e. determine which peaks in the 1H NMR correspond to which hydrogens in the product). The peaks have been labeled 1-8 on the spectrum, and the relevant hydrogens Ha-Hh below. b) Calculate the coupling constant between He and Hf. Explain how can this can help determine the stereochemistry (i.e. cis vs. trans) of the double bond. (7) Acetone is a symmetrical molecule, so there are two positions that can react. Draw the product you would expect to obtain if you used two molar equivalents of vanillin rather than one. c) Acetone is a symmetrical molecule, so there are two positions that can react. Draw the product you would expect to obtain if you used two molar equivalents of vanillin rather than one.
1 answer:
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Answer:- selenium, Se.
Explanations:- When an element gain electrons then it becomes negatively charged means it forms it's anion. Total electrons of the anion are the sum of electrons and the charge of the anion. In our problem, the element is q and it forms ion. The Total electrons for the anion
= electrons of q + 2
As per the given info, there are 36 electrons in ion.
So, 36 = electrons of q + 2
electrons of q = 36 - 2
electrons of q = 34
q, the neutral atom has 34 electrons means it's atomic number is 34. If we check out the periodic table then the element with atomic number 34 is Selenium, Se.