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2 years ago

Suppose you have 200.0 mL of a 0.750 M sodium hydroxide solution. How many

Chemistry

1 answer:

Nikolay [14]2 years ago

5 0

Answer:

0.15 moles of sodium hydroxide are in the solution.

Explanation:

Molarity is a unit for expressing concentration of solutions. Molarity is defined as the number of moles of solute per liter of solution.

The molarity of a solution is calculated by dividing the moles of the solute by the liters of the solution:

$Molarity (M)=\frac{number of moles of solute}{volume}$

Molarity is expressed in units ( $\frac{moles}{liter}$ ).

So, a molarity of 0.750 M indicates that 0.750 moles are present in 1 L of solution. Then the following rule of three can be applied: if in 1000 mL (being 1 L = 1000 mL) there are 0.750 moles, in 200 mL how many moles are there?

$amount of moles=\frac{200 mL*0.750 moles}{1000 mL}$

amount of moles=0.15

<u><em> 0.15 moles of sodium hydroxide are in the solution.</em></u>

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2 years ago

When the reaction CO2(g) + H2(g) ⇄ H2O(g) + CO(g) is at equilibrium at 1800◦C, the equilibrium concentrations are found to be [C

UNO [17]

Answer:

The new molar concentration of CO at equilibrium will be :[CO]=1.16 M.

Explanation:

Equilibrium concentration of all reactant and product:

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Equilibrium constant of the reaction :

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K = 4

$CO_2(g) + H_2(g) \rightleftharpoons H_2O(g) + CO(g)$

Concentration at eq'm:

0.24 M 0.24 M 0.48 M 0.48 M

After addition of 0.34 moles per liter of $CO_2$ and $H_2$ are added.

(0.24+0.34) M (0.24+0.34) M (0.48+x)M (0.48+x)M

Equilibrium constant of the reaction after addition of more carbon dioxide and water:

$K=4=\frac{(0.48+x)M\times (0.48+x)M}{(0.24+0.34)\times (0.24+0.34) M}$

$4=\frac{(0.48+x)^2}{(0.24+0.34)^2}$

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2 years ago

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2 years ago

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Use the formula, Q= mcT

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FrozenT [24]

Answer:

d) All have identical pressures

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