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aleksandrvk [35]
1 year ago
9

Suppose you have 200.0 mL of a 0.750 M sodium hydroxide solution. How many

Chemistry
1 answer:
Nikolay [14]1 year ago
5 0

Answer:

0.15 moles of sodium hydroxide are in the solution.

Explanation:

Molarity is a unit for expressing concentration of solutions. Molarity is defined as the number of moles of solute per liter of solution.

The molarity of a solution is calculated by dividing the moles of the solute by the liters of the solution:

Molarity (M)=\frac{number of moles of solute}{volume}

Molarity is expressed in units (\frac{moles}{liter}).

So, a molarity of 0.750 M indicates that 0.750 moles are present in 1 L of solution. Then the following rule of three can be applied: if in 1000 mL (being 1 L = 1000 mL) there are 0.750 moles, in 200 mL how many moles are there?

amount of moles=\frac{200 mL*0.750 moles}{1000 mL}

amount of moles=0.15

<u><em> 0.15 moles of sodium hydroxide are in the solution.</em></u>

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You have 49.8 g of O2 gas in a container with twice the volume as one with CO2 gas. The pressure and temperature of both contain
IrinaVladis [17]

Answer:

34.2 g is the mass of carbon dioxide gas one have in the container.

Explanation:

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{49.8\ g}{32\ g/mol}

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Since pressure and volume are constant, we can use the Avogadro's law  as:-

\frac {V_1}{n_1}=\frac {V_2}{n_2}

Given ,  

V₂ is twice the volume of V₁

V₂ = 2V₁

n₁ = ?

n₂ = 1.55625 mol

Using above equation as:

\frac {V_1}{n_1}=\frac {V_2}{n_2}

\frac {V_1}{n_1}=\frac {2\times V_1}{1.55625}

n₁ = 0.778125 moles

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Mass of CO_2 = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g

<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>

5 0
1 year ago
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