answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yuri [45]
2 years ago
5

You have 49.8 g of O2 gas in a container with twice the volume as one with CO2 gas. The pressure and temperature of both contain

ers are the same. Calculate the mass of carbon dioxide gas you have in the container.
Chemistry
1 answer:
IrinaVladis [17]2 years ago
5 0

Answer:

34.2 g is the mass of carbon dioxide gas one have in the container.

Explanation:

Moles of O_2:-

Mass = 49.8 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{49.8\ g}{32\ g/mol}

Moles_{O_2}= 1.55625\ mol

Since pressure and volume are constant, we can use the Avogadro's law  as:-

\frac {V_1}{n_1}=\frac {V_2}{n_2}

Given ,  

V₂ is twice the volume of V₁

V₂ = 2V₁

n₁ = ?

n₂ = 1.55625 mol

Using above equation as:

\frac {V_1}{n_1}=\frac {V_2}{n_2}

\frac {V_1}{n_1}=\frac {2\times V_1}{1.55625}

n₁ = 0.778125 moles

Moles of carbon dioxide = 0.778125 moles

Molar mass of CO_2 = 44.0 g/mol

Mass of CO_2 = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g

<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>

You might be interested in
If an electronic balance reports an object weighing 35.9920g what will be displayed when
Nat2105 [25]

Answer:

2.0000 g

Explanation:

It will show the number out to the 4th decimal place.  Exactly 2 g will be displayed as 2.0000 g.

8 0
2 years ago
The Keq for the equilibrium below is 5.4 × 1013 at 480.0 °C. 2NO (g) + O2 (g) 2NO2 (g) What is the value of Keq at this temperat
kodGreya [7K]

<u>Answer:</u> The equilibrium constant for NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g) equation is 1.36\times 10^{-7}

<u>Explanation:</u>

The given chemical equation follows:

2NO(g)+O_2(g)\rightleftharpoons 2NO_2(g)

The value of equilibrium constant for the above equation is K_{eq}=5.4\times 10^{13}

Calculating the equilibrium constant for the given equation:

NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g)

The value of equilibrium constant for the above equation will be:

K'_{eq}=\frac{1}{\sqrt{K_{eq}}}\\\\K'_{eq}=\frac{1}{\sqrt{5.4\times 10^{13}}}\\\\K'_{eq}=1.36\times 10^{-7}

Hence, the equilibrium constant for NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g) equation is 1.36\times 10^{-7}

5 0
1 year ago
Octane is a liquid component of gasoline. Given the following vapor pressures of octane at various temperatures, estimate the bo
Hitman42 [59]

Answer:

110.8 ºC

Explanation:

To solve this problem we will make use of the Clausius-Clayperon equation:

lnP = - ΔHºvap/RT + C

where P is the pressure, ΔHºvap is the enthalpy of vaporization, R is the gas constant, T is the temperature, and C is a constant of integration.

Now this equation has a form y = mx + b where

y = lnP

x = 1/T

m = -ΔHºvap/R

Now we have to assume that ΔHºvap remains constant which is a good asumption given the narrow range of temperatures in the data ( 104-125) ºC

Thus what we have to do is find the equation of the best fit for this data using a  software as excel or your calculator.

T ( K)               1/T                  ln P

377               0.002653       5.9915

384              0.002604       6.2115

390              0.002564       6.3969

395              0.002532       6.5511

398              0.002513        6.6333

The best line has a fit:

y = -4609.5 x  + 18.218

with R² = 0.9998

Now that we have the equation of the line, we simply will substitute for a pressure of 496 mm in Leadville.

ln(496) = -4609.5(1/Tb) + 18.218

6.2066 = -4609.5(1/Tb) +18.218

⇒ 1/Tb = (18.218 - 6.2066)/4609.5 = 0.00261

Tb = 383.76 K  = (383.76 -273)K = 110.8 ºC

Notice we have touse up to 4 decimal places since rounding could lead to an erroneous answer ( i.e boiling temperature greater than 111, an impossibility given the data in the question). This is as a result of the value 496 mmHg so close to 500 mm Hg.

Perhaps that is the reason the question was flagged.

7 0
2 years ago
The researcher performed a follow-up experiment to measure the rate of oxygen consumption by muscle and brain cells. Predict the
Naddik [55]

Answer:

Mitochondria are abundantly present in mammalian cells. Their fraction varies from tissue to tissue, ranging from <1% (volume) in white blood cells to 35% in heart muscle cells. However, mitochondria should not be thought of as single entities, but rather a dynamic network that continuously undergoes fission and fusion processes. In skeletal muscle, mitochondria exist as a reticular membrane network. The subsarcolemmal (SS) and intermyofibrillar (IMF) mitochondria are located in distinct subcellular regions, and they possess subtle differences in biochemical and functional properties that are characterized by their anatomical locations. SS mitochondria lie directly beneath the sarcolemmal membrane and the IMF mitochondria are located in close contact with the myofibril. Their different properties are likely to influence their capacity for adaptation. SS mitochondria account for 10-15% of the mitochondrial volume and this population has been shown to be more susceptible to adaptation than the IMF mitochondria. However, the IMF mitochondria were found to have higher rates of protein synthesises, enzyme activities and respiration (1).

Explanation:

0 0
2 years ago
Read 2 more answers
A molecular orbital is a region of space in a covalent species where electrons are likely to be found. The combination of two at
lara [203]

Answer:

bonding molecular orbital is lower in energy

antibonding molecular orbital is higher in energy

Explanation:

Electrons in bonding molecular orbitals help to hold the positively charged nuclei together, and they are always lower in energy than the original atomic orbitals.

Electrons in antibonding molecular orbitals are primarily located outside the internuclear region, leading to increased repulsions between the positively charged nuclei. They are always higher in energy than the parent atomic orbitals.

5 0
1 year ago
Other questions:
  • What alkene reacts the fastest with HBr?
    8·2 answers
  • ) A round or oval hole through a bone, which contains blood vessels and/or nerves, is called a __________.
    14·1 answer
  • What mass of lif is contained in 18.66 g of a 20.0% by mass solution of lif in water?
    10·1 answer
  • The gaseous product of a reaction is collected in a 25.0-l container at 27
    5·1 answer
  • A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting sol
    6·1 answer
  • 3. From the following formula, calculate the quantities required to make 5 lb o hydrophilic ointment. Methylparaben 0.25 g Propy
    10·1 answer
  • 1) Aluminum sulphate can be made by the following reaction: 2AlCl3(aq) + 3H2SO4(aq) Al2(SO4)3(aq) + 6 HCl(aq) It is quite solubl
    12·1 answer
  • Calculate the mass in grams of each sample.
    15·1 answer
  • Name 3 common compounds, using both their chemical symbol and their name
    13·1 answer
  • Draw the major product for the reaction of 1-butyne with water in the presence of catalytic TfOH (i.e., CF3SO3H). Then answer th
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!