The formula for chromium (III) phosphate trihydrate is CrPO4- 3H20. This compound if in the anhydrous state, exists as a green crystal whereas a hydrated form violet crystal. The formula for cobalt(II) phosphate octahydrate is Co3(PO4)2•8H2O.
601 expressed as an integer is 3.
An integer refers to a whole number, a number which do not contain any decimal point.
To express any given number as an integer, just count the number of significant figures in the number and write this down as a whole number.
Answer:
a. Yes, it is flammable.
b. It can cause hazard and carcinogenic effect.
Explanation:
A. Yes, the vapor in the vessel is flammable because it is an organic solvent with a very low boiling point. For this reason, less energy can vaporize it. Therfore, a little high temperature or energy causes it to be very reactive and flammable.
B. - Being flammable makes it hazardous, that is, it is capable of being ignited and can burn easily, which makes it really dangerous.
- It results in carcinogenic effect on the body. Substances that cause carcinogenic effect are capable of increasing the risk of cancer. They might contain compounds that can initiate tumor.
When the temperature is high, the risk of explosion increases. Due to the fact that at higher temperature, the kinetic energy of the atoms which result in an increase in the volume and finally blasting of the vessel.
Answer:
The mass of object is 0.5 Kg.
Explanation:
Given data:
Acceleration of object = 12.0 m/s²
Force on object = 6.0 N
Mass of object = ?
Solution:
Formula:
F = m×a
F = force
m = mass
a = acceleration
Now we will put the values in formula.
6.0 N = m × 12.0 m/s²
m = 6.0 N / 12.0 m/s²
( N = kg.m/s²)
m = 0.5 kg
The mass of object is 0.5 Kg.
Answer:
A.) 34.866 x 10¯23 g/atom
B.) 2.64 x 10^22 atoms in 1 cm3
C.) 1 atoms per unit cell
Explanation:
A) Calculate the average mass of one atom of polonium:
210g mol¯1 ÷ 6.022 x 1023 atoms mol¯1 = 34.866 x 10¯23 g/atom
B) Determine atoms in 1 cm3:
9.19g / 34.866x 10¯23 g/atom = 2.64 x 10^22 atoms in 1 cm3
Determine volume of the unit cell:
(3.37 x 10¯8 cm)3 = 3.827 x 10¯23 cm3
Determine number of unit cells in 1 cm3:
1 cm3 / 3.827 x 10¯23 cm3 = 2.61 x 1022 unit cells
C) Determine atoms per unit cell:
2.64 x 1022 atoms / 2.61 x 1022 unit cells = 1 atoms per unit cell
