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belka [17]
2 years ago
9

At 15°C, the value of Kw is 4.5 × 10⁻¹⁵. What is the equilibrium concentration of OH⁻ at this temperature?

Chemistry
1 answer:
MaRussiya [10]2 years ago
5 0
[H3O+][OH-] = 4.5 x 10^-15
[H3O+] = [OH-] = 6.7 x 10^-8 M

Explanation: do the math
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Which of these is a difference between a single skin cell and the skin tissue that covers an entire hand?
fgiga [73]

Answer:

c

Explanation:

the cells grow more than the tissue

7 0
2 years ago
Read 2 more answers
A laboratory utilizes a mixture of 10% dimethyl sulfoxide (DMSO) in the freezing and long-term storage of embryonic stem cells.
Mars2501 [29]

Answer:

The correct answer is "1.0100".

Explanation:

Let the volume of mixture be 100 ml.

then,

The volume of DMSO will be 10 mL as well as that of water will be 90 mL.

DMSO will be:

= 10\times 1.1004

= 11.004 \ g

The total mass of mixture will be:

= 90+11.004

= 101.004 \ g

Density of mixture will be:

= \frac{Mass}{Volume}

= \frac{101.004}{100}

= 1.01004 \ g/mL

hence,

Specific gravity of mixture will be:

= \frac{Density \ of \ mixture}{Density \ of \ water}

= \frac{1.01004}{1}

= 1.0100

3 0
2 years ago
The volume of a gas at 7.00°c is 49.0 ml. if the volume increases to 74.0 ml and the pressure is constant, what will the tempera
marshall27 [118]
Using charles law
v1/t1=v2/t2
v1=49ml
v2=74
t1=7+273=280k
t2=?
49/280=74/t2
0.175=74/t2  cross multiply
0.175t2=74
t2=74/0.175
t2=422k or 149celcius
8 0
2 years ago
The halogens, alkali metals, and alkaline earth metals have __________ valence electrons, respectively.
natima [27]
The valence electrons are as follows for these groups of elements:

Halogen- SEVEN  (halogens are group 7 elements that need one electron for the octet rule to be achieved)

Alkali Metals - ONE  (these are group one elements that lose a single electron to form an octet and cation)

Alkaline Earth Metals - TWO (group two elements that lose two electrons to form 2+ cations)

8 0
2 years ago
A 1.87 L aqueous solution of KOH contains 155 g of KOH . The solution has a density of 1.29 g/mL . Calculate the molarity ( M ),
lbvjy [14]

Answer:

[KOH] = 1.47 M

[KOH] = 1.22 m

KOH = 6.86 % m/m

Explanation:

Let's analyse the data

1.87 L is the volume of solution

Density is 1.29 g/mL → Solution density

155 g of KOH → Mass of solute

Moles of solute is (mass / molar mass) = 2.76 moles.

Molarity is mol/L → 2.76 mol / 1.87 L = 1.47 M

Let's determine, the mass of solvent.

Molality is mol of solute / 1kg of solvent

We can use density to find out the mass of solution

Mass of solution - Mass of solute = Mass of solvent

Density = Mass / volume

1.29 g/mL = Mass / 1870 mL

Notice, we had to convert L to mL, cause the units of density.

1.29 g/mL . 1870 mL = Mass → 2412.3 g

2412.3 g - 155 g = 2257.3 g of solvent

Let's convert the mass of solvent to kg

2257.3 g / 1000 = 2.25kg

2.76 mol / 2.25kg = 1.22 m (molality)

% percent by mass = mass of solute in 100g of solution.

(155 g / 2257.3 g) . 100g = 6.86 % m/m

5 0
2 years ago
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