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2 years ago

How many grams of water will form if 10.54 g H2 react with 95.10 g O2?

Chemistry

2 answers:

sergiy2304 [10]2 years ago

5 0

Answer:

94.0 g H2O

Explanation:

uranmaximum [27]2 years ago

5 0

Answer:94.0 g H2O

Explanation:

2H2 + O2 --> 2H2O

The

question asked me how many grams of water will form if 10.54 g H2 react with 95.10 g O2.

The correct answer was 94.0g of H2O I got from

10.54g H2 * 1 mol H2/2.02 g/mol H2 * 2 mol H2O/2 mol H2 = 5.22 mol H2O

95.10g O2* 1 mol O2/32 g/mol O2 * 2 mol H2O/1 mol O2 = 5.94 mol H2O

The limiting reactant is 5.22 mol, which 5.22 mol H2O * 18.01 g/mol H2O = 94.0g H2O.

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Compound A is an organic compound which contains Carbon, Hydrogen and Oxygen. When 0.240g of the vapour of A is slowly passed ov

Keith_Richards [23]

Answer:

1) 0.009 61 g C; 2) 0.008 00 mol C

Step-by-step explanation:

You know that you will need a balanced equation with masses, moles, and molar masses, so gather all the information in one place.

M_r: 12.01 44.01

C + ½O₂ ⟶ CO₂

m/g: 0.352

1) Mass of C

Convert grams of CO₂ to grams of C

44.01 g CO₂ = 12.01 g C

Mass of C = 0.352 g CO₂ × 12.01 g C/44.01 g CO₂

Mass of C = 0.009 61 g C

2) Moles of C

Convert mass of C to moles of C.

1 mol C = 12.01 g C

Moles of C = 0.00961 g C × (1 mol C/12.01 g C)

Moles of C = 0.008 00 mol C

All the carbon comes from Compound A, so there are 0.008 00 mol C in Compound A.

7 0

2 years ago

Beryllium has a nucleus composed of protons and neutrons. Given the data, how many protons are in a typical Beryllium nucleus?

Jlenok [28]

Atoms are made of 3 types of subatomic particles ; protons, neutrons and electrons

protons and neutrons are located inside the nucleus and electrons are found in energy shells around the nucleus. Protons are positively charged, electrons are negatively charged and neutrons are neutral. elements in their ground state are neutral with equal amounts of protons and electrons.

Atomic number is the number of protons. atomic number is characteristic for the element.

atomic number of Be is 4 therefore Be has 4 protons

answer is B. 4

5 0

2 years ago

Read 2 more answers

How many atoms of Ca are present in 80.156 grams of Ca? (4 points) 1.2044 × 1024 2.4088 × 1024 4.8270 × 1025 1.9346 × 1027

Alika [10]

Answer: 1.2044 × 10^24

Explanation:

1 mole of calcium is 40 gram

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms, also 1 mole of calcium is 40gram

So, 1 mole of calcium = 6.02 x 10^23 atoms

Also, 1 mole of calcium is 40gram

40 grams of calcium = 6.02 x 10^23 atoms

80.156 grams of calcium = Z atoms

To get the value of Z, cross multiply:

Z atoms x 40 grams = 6.02 x 10^23 atoms x 80.156 grams

40Z = 482.54 x 10^23

Z = (482.54 x 10^23/40)

Z = 12.06 x 10^23

Put result in standard form

Z = 1.206 x 10^24 atoms

Thus, 1.206 x 10^24 atoms of Ca are present in 80.156 grams of Ca

6 0

2 years ago

Read 2 more answers

Approximately 220 million tires are discarded in the U.S. each year. These tires present a disposal problem because they take up

Andreas93 [3]

Answer:

2667 tires are needed to meet the demand of ten homes for one year.

Explanation:

According to the Second Law of Thermodynamics, only a part of generated energy when tires are burned can be utilized due to irreversibilities associated with finite temperature differences. The energy from a tire that can be transformed into electricity ( $E_{out}$ ), measured in kilowatt-hours, is estimated by definition of efficiency:

$E_{out} = \eta \cdot E_{in}$

Where:

$\eta$ - Efficiency, dimensionless.

$E_{in}$ - Energy liberated by burning, measured in kilowatt-hours.

Given that $\eta = 0.5$ and $E_{in} = 75\,kWh$ , the amount of energy per year generated by a tire is:

$E_{out} = 0.5\cdot (75\,kWh)$

$E_{out} = 37.5\,kWh$

Now, the amount of tires needed to meet the demand of then homes for one year is:

$n = \frac{(10\,homes)\cdot \left(10000\,\frac{kWh}{home} \right)}{37.5\,\frac{kWh}{tire} }$

$n = 2666.667\,tires$

2667 tires are needed to meet the demand of ten homes for one year.

8 0

2 years ago

How many grams of sodium bromide must be dissolved in 400.0 g of water to produce a 0.500 molal solution?

lana [24]

Answer:

The answer is 20.6 grams.

Explanation:

Molality describes the concentration of a solution. It can be defined as the number of moles of a solute dissolved in 1 kilogram of solvent. Then it is equal to the moles of solute (the substance that dissolves) divided by the kilograms of solvent (the substance used to dissolve):

$Molality=\frac{number of moles of solute}{kilogram of solvent}$

The molality is expressed in units ( $\frac{moles}{kg}$ ).

So, you can apply the following rule of three with the solution being 0.5 molal: if in 1 kg of solution there are 0.5 moles of solute, in 0.4 kg (400 g, being 1kg = 1000g) how many moles of solute are there?

$moles=\frac{0.4 kg*0.5 moles}{1 kg}$

moles=0.2 moles

Now, you know:

Na: 23 g/mole
Br: 80 g/mole

Then, The molar mass of sodium bromide NaBr is

NaBr= 23 g/mole + 80 g/mole= 103 g/mole

Now a new rule of three applies, if in 1 mole of sodium bromide there are 103 grams, in 0.2 mole how much mass is there?

$mass=\frac{0.2 moles*103 grams}{1 mole}$

mass= 20.6 grams

The answer is 20.6 grams.

6 0

2 years ago