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Alex Ar [27]
1 year ago
8

When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several

cellular structures. Which of the following correctly describes the order in which these structures will be encountered by the ion? When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several cellular structures. Which of the following correctly describes the order in which these structures will be encountered by the ion? primary cell wall → plasma membrane → cytoplasm → secondary cell wall → vacuole plasma membrane → primary cell wall → cytoplasm → vacuole secondary cell wall → plasma membrane → primary cell wall → cytoplasm → vacuole primary cell wall → plasma membrane → lysosome → cytoplasm → vacuole primary cell wall → plasma membrane → cytoplasm → vacuole
Chemistry
1 answer:
insens350 [35]1 year ago
4 0
<h3><u>Answer;</u></h3>

C) primary cell wall → plasma membrane → cytoplasm → vacuole

<h3><u>Explanation;</u></h3>
  • The cell wall is the protective outer layer of a plant cell, that gives the cell strength and structure, and also filters molecules that pass in and out of the cell.
  • Cell membrane acts as a semi-permeable barrier separating the inside of the cell from the outside of the cell. The membrane allows regulation of what enters/exits the cell and how quickly.
  • Cytoplasm is the jelly-like fluid that fills a cell. It is responsible for giving a cell its shape and also helps to fill out the cell and keeps organelles in their place.
  • Vacuoles are membrane-bound sacs within the cytoplasm of a cell that function in several different ways. They functional in providing structural support, as well as serving functions such as storage, waste disposal, protection, and growth.
  • <u>Potassium ion from the extracellular environment will move to the cell vacuole via the cell wall, the cell membrane and then via the cytoplasm to the vacuole.</u>
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The pKs of succinic acid are 4.21 and 5.64. How many grams of monosodium succinate (FW = 140 g/mol) and disodium succinate (FW =
Varvara68 [4.7K]

Answer:

9.744g of monosodium succinate.

4.925g of disodium succinate.

Explanation:

To find pH of the buffer produced by the mixture of monosodium succinate-Disodium succinate is obtained from H-H equation:

pH = pKa + log ([Na₂Suc] / [NaHSuc])

As you want a pH of 5.28 and pKa is 5.64:

5.28 = 5.64 + log ([Na₂Suc] / [NaHSuc])

-0.36 = log ([Na₂Suc] / [NaHSuc])

0.4365 = ([Na₂Suc] / [NaHSuc]) <em>(1)</em>

<em />

As total concentration of the buffer is 100mM = 0.100M:

0.100M = [Na₂Suc] + [NaHSuc] <em>(2)</em>

Replacing (2) in (1):

0.4365 = (0.100M - [NaHSuc] / [NaHSuc])

0.4365 = (0.100M - [NaHSuc] / [NaHSuc])

0.4365 [NaHSuc] = 0.100M - [NaHSuc]

1.4365 [NaHSuc] = 0.100M

[NaHSuc] = 0.0696M

And:

[Na₂Suc] = 0.0304M

As volume of the buffer is 1L:

[NaHSuc] = 0.0696 moles

[Na₂Suc] = 0.0304 moles

Using molar mass of both substances:

Mass of monosodium succinate:

0.0696moles * (140g / 1mol) =<em> 9.744g of monosodium succinate.</em>

Mass of disodium succinate:

0.0304moles * (162g / 1mol) =<em> 4.925g of disodium succinate.</em>

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5 0
2 years ago
What pressure does 3.54 moles of chlorine gas at 376 k exert on the walls of it 51.2 l container? I'm Lazy sooooo
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Answer:

The answer to your question is P = 2.13 atm

Explanation:

Data

Pressure = ?

number of moles = 3.54

Temperature = 376 °K

Volume = 51.2 L

R = 0.08205 atm L/mol°K

Formula

PV = nRT

- Solve for P

  P = nRT / V

- Substitution

  P = (3.54)(0.08205)(376) / 51.2

- Simplification

  P = 109.21 / 51.2

Result

 P = 2.13 atm  

6 0
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1 year ago
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when 
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change    -X                   +X          +X
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