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Alex Ar [27]
2 years ago
8

When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several

cellular structures. Which of the following correctly describes the order in which these structures will be encountered by the ion? When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several cellular structures. Which of the following correctly describes the order in which these structures will be encountered by the ion? primary cell wall → plasma membrane → cytoplasm → secondary cell wall → vacuole plasma membrane → primary cell wall → cytoplasm → vacuole secondary cell wall → plasma membrane → primary cell wall → cytoplasm → vacuole primary cell wall → plasma membrane → lysosome → cytoplasm → vacuole primary cell wall → plasma membrane → cytoplasm → vacuole
Chemistry
1 answer:
insens350 [35]2 years ago
4 0
<h3><u>Answer;</u></h3>

C) primary cell wall → plasma membrane → cytoplasm → vacuole

<h3><u>Explanation;</u></h3>
  • The cell wall is the protective outer layer of a plant cell, that gives the cell strength and structure, and also filters molecules that pass in and out of the cell.
  • Cell membrane acts as a semi-permeable barrier separating the inside of the cell from the outside of the cell. The membrane allows regulation of what enters/exits the cell and how quickly.
  • Cytoplasm is the jelly-like fluid that fills a cell. It is responsible for giving a cell its shape and also helps to fill out the cell and keeps organelles in their place.
  • Vacuoles are membrane-bound sacs within the cytoplasm of a cell that function in several different ways. They functional in providing structural support, as well as serving functions such as storage, waste disposal, protection, and growth.
  • <u>Potassium ion from the extracellular environment will move to the cell vacuole via the cell wall, the cell membrane and then via the cytoplasm to the vacuole.</u>
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Answer:

A scandium-48 nucleus undergoes beta-minus decay to produce a titanium-48 nucleus.

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However, in a beta-minus decay, the atomic number of the nucleus increases by one. In a beta-plus decay, the atomic number decreases by one.

Each beta-minus decay releases one electron and one electron antineutrino. Each beta-plus decay releases one positron and one electron neutrino.

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This question did not specify whether the decay here is beta-plus or a beta-minus. However, the relative atomic mass of this element can give a rough estimate of the mode of decay.

Each element (e.g, \rm Sc) can have multiple isotopes. These isotopes differ in mass. The relative atomic mass of an element is an average  across all isotopes of this element. This mass is weighted based on the relative abundance of the isotopes. Its value should be closest to the most stable (and hence the most abundant) isotope.

The mass number of scandium-48 is significantly larger than the relative atomic mass of this element. In other words, this isotope contains more neutrons than isotopes that are more stable. There's a tendency for that neutron to convert to a proton- by beta-minus decay, for example.

The atomic number of the nucleus will increase by 1. 21 + 1 = 22. That corresponds to titanium. The mass number stays the same at 48. Hence the daughter nucleus would be titanium-48. Note that two other particles: one electron and one electron \rm e^{-} and one antineutrino \bar{v}_{\text{e}} (note the bar.) The neutrino helps balance the lepton number of this reaction.

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