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Tresset [83]
2 years ago
13

A) To generate the spectrum above a source capable of producing electromagnetic radiation with an energy of 7 * 10 ^ 4 * k * J p

er mole of photons was used. Such radiaton is from which region of the electromagnetic spectrum. Justify your answer with a calculation
Chemistry
2 answers:
marin [14]2 years ago
3 0

Answer:

Gamma

Explanation:

I'm not sure how to do it without calculations but:

E=hv

7*10^7 J/mol=6.626*10^34 Js * v

v=1*10^41

Gamma rays.

More here: https://www.hasd.org/faculty/AndrewSchweitzer/spectroscopy.pdf

-Dominant- [34]2 years ago
3 0

Answer:

These radiations is from X-rays region of the electromagnetic spectrum.

Explanation:

Energy of the 1 photon =E=7\times 10^4 kJ/mol

Energy of the photon :

E=\frac{7\times 10^4 kJ/mol}{N_A}

=\frac{7\times 10^7 J/mol}{6.022\times 10^{23} mol^{-1}} (1 kJ=1000 J)

E=1.1624\times 10^{-16} J

E=\frac{hc}{\lambda }

\lambda =\frac{6.634\times 10^{-34} Js\times 3\times 10^8 m/s}{1.1624\times 10^{-16} J}

E=1.712\times 10^{-9} m = 1.712 nm

These radiations is from X-rays region(0.1 nm to 10 nm) of the electromagnetic spectrum.

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What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon
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Answer:

Theoretical yield = 31.8 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

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The formula for the calculation of moles is shown below:

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The formation of the product is governed by the limiting reagent. So,

1 mole of aluminium oxide on reaction forms 2 moles of aluminium.

0.5885 mole of aluminium oxide on reaction forms 2\times 0.5885 moles of aluminium.

Moles of aluminium = 1.177 moles

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