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Tresset [83]
2 years ago
13

A) To generate the spectrum above a source capable of producing electromagnetic radiation with an energy of 7 * 10 ^ 4 * k * J p

er mole of photons was used. Such radiaton is from which region of the electromagnetic spectrum. Justify your answer with a calculation
Chemistry
2 answers:
marin [14]2 years ago
3 0

Answer:

Gamma

Explanation:

I'm not sure how to do it without calculations but:

E=hv

7*10^7 J/mol=6.626*10^34 Js * v

v=1*10^41

Gamma rays.

More here: https://www.hasd.org/faculty/AndrewSchweitzer/spectroscopy.pdf

-Dominant- [34]2 years ago
3 0

Answer:

These radiations is from X-rays region of the electromagnetic spectrum.

Explanation:

Energy of the 1 photon =E=7\times 10^4 kJ/mol

Energy of the photon :

E=\frac{7\times 10^4 kJ/mol}{N_A}

=\frac{7\times 10^7 J/mol}{6.022\times 10^{23} mol^{-1}} (1 kJ=1000 J)

E=1.1624\times 10^{-16} J

E=\frac{hc}{\lambda }

\lambda =\frac{6.634\times 10^{-34} Js\times 3\times 10^8 m/s}{1.1624\times 10^{-16} J}

E=1.712\times 10^{-9} m = 1.712 nm

These radiations is from X-rays region(0.1 nm to 10 nm) of the electromagnetic spectrum.

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A sample of neon gas at a pressure of 1.08 atm fills a flask with a volume of 250 mL at a temperature of 24.0 °C. If the gas is
musickatia [10]

Answer:

124.91mL

Explanation:

Given parameters:

P₁  = 1.08atm

V₁  = 250mL

T₁  = 24°C

P₂  = 2.25atm

T₂  = 37.2°C

V₂  = ?

Solution:

To solve this problem, we are going to apply the combined gas law;

              \frac{P_{1} V_{1} }{T_{1} }   =  \frac{P_{2} V_{2} }{T_{2} }

P, V and T represents pressure, volume and temperature

1 and 2 delineates initial and final states

Convert the temperature to kelvin;

        T₁  = 24°C,  T₁   = 24 + 273 = 297K

        T₂  = 37.2°C , T₂  = 37.2 + 273  = 310.2K

Input the variables and solve for V₂

        \frac{1.08 x 250}{298} = \frac{2.25 x V_{2} }{310.2}

           V₂ = 124.91mL

6 0
2 years ago
Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution
Aliun [14]

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}

or,

\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}

First we have to calculate the equivalent weight of solute.

Molar mass of solute PO_4^{3-} = 94.97 g/mole

\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq

Now we have to calculate the normality of solution.

\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L

Therefore, the normality of the solution is, 30.006 N

5 0
2 years ago
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