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LiRa [457]
2 years ago
5

Solid aluminum metal and diatomic bromine liquid react spontaneously to form a solid product. give the balanced chemical equatio

n (including phases) that describes this reaction. indicate the phases using abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively.
Chemistry
2 answers:
Digiron [165]2 years ago
4 0

Explanation:

Aluminium being metal reacts violently with liquid bromine. It is a highly exothermic reaction during which large amount of heat is released.

Aluminum when reacts with liquid bromine it gives aluminium bromide as a product.

The balanced chemical equation is given as:

2Al(s) + 3Br_2(l)\rightarrow 2AlBr_3(s)

According stoichiometry, 2 moles of aluminum metal react with 3 mole of liquid bromine to give 2 moles of aluminum bromide.

kaheart [24]2 years ago
3 0
Aluminum has a chemical formula of Al, while diatomic bromine has a chemical formula of Br₂. The balanced chemical reaction is shown below:

<em>2 Al (s) + 3 Br₂ (l) → 2 AlBr₃ (s)</em>

The solid product is called Dibromoaluminum. The stoichiometric coefficients are used to balance the reaction to obey the Law of Conservation of Mass.
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As ice transforms into steam, A)new molecules are formed. B)the types of atoms are changed. C)energy is absorbed by the molecule
ra1l [238]
<span>This is an example of a substance changing state, a physical change, the molecules are changed, but the atoms themselves do not change, just their arrangement, and the mass of the molecules is the same. Therefor energy is absorbed by the molecules, as energy is required to change the state or physicality of a molecule structure.Hope this helps. Let me know if you need additional help!</span>
8 0
2 years ago
Read 2 more answers
A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor
AlexFokin [52]

Answer : The partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of C_2HBrClF_3 = 15.0 g

Mass of O_2 = 22.6 g

Molar mass of C_2HBrClF_3 = 197.4 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_2HBrClF_3 and O_2.

\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole

and,

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole

Now we have to calculate the mole fraction of C_2HBrClF_3 and O_2.

\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971

and,

\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903

Now we have to partial pressure of C_2HBrClF_3 and O_2.

According to the Raoult's law,

p^o=X\times p_T

where,

p^o = partial pressure of gas

p_T = total pressure of gas

X = mole fraction of gas

p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T

p_{C_2HBrClF_3}=0.0971\times 862torr=84torr

and,

p_{O_2}=X_{O_2}\times p_T

p_{O_2}=0.903\times 862torr=778torr

Therefore, the partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

6 0
1 year ago
9 The Haber process is a reversible reaction. N2(g) + 3H2(g) 2NH3(g) The reaction has a 30% yield of ammonia. Which volume of am
Illusion [34]

Answer:  3.36 L of ammonia gas

Explanation:

The balanced chemical reaction is:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)  

According to stoichiometry :

3 moles of H_2 produce = 2 moles of NH_3

Thus 0.75 moles of H_2 will producee=\frac{2}{3}\times 0.75=0.50moles  of NH_3

But as percent yield is 30 %, amount of ammonia produced = \frac{30}{100}\times 0.50moles=0.15moles

According to ideal gas equation:

PV=nRT

P = pressure  = 1 atm

V = Volume  = ?

n = number of moles = 0.15

R = gas constant =0.0821Latm/Kmol

T =temperature =273K

V=\frac{nRT}{P}

V=\frac{0.15\times 0.0820 L atm/K mol\times 273K}{1atm}=3.36L

Thus 3.36 L of ammonia gas is obtained by reacting 0.75 moles of hydrogen with excess nitrogen.

3 0
1 year ago
Which radioisotopes have the same decay mode and have half-lives greater than
AveGali [126]

The correct answer is (3)


I-131 and P-32


The explanation:


according to attached table:


- we can see that the half life of p 32 is 14.28d (more than one hour)

- and the half life of I-131 is 8.021 d (more than one hour)


and They both have β- decay mode and with half-lives greater than hour.


4 0
2 years ago
Read 2 more answers
You have just started working at a swimming pool supply store and they have nitric acid on their shelves. In order to help custo
Tanzania [10]

Answer:

The concentration of hydronium ions is 0.0155 mol/L

Explanation:

The aqueous solution ionization reaction for nitric acid is as follows;

HNO₃ + H₂O → NO₃⁻ + H₃O⁺

Whereby HNO₃ is a strong acid and it undergoes complete ionization in an aqueous solution

Hence one mole of HNO₃ produces one mole of H₃O⁺ ions

0.0155 mol/L HNO₃ will have 0.0155 moles of H₃O⁺ in one liter of the solution

The concentration of hydronium ions = 0.0155 mol/L.

7 0
2 years ago
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