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kodGreya [7K]
2 years ago
13

A raindrop has a mass of 50. mg and the Pacific Ocean has a mass of 7.08 x 10^20 kg. what is the mass of 1 mole of raindrops? Ho

w many moles of raindrops are in the Pacific Ocean?
Chemistry
2 answers:
Anna007 [38]2 years ago
7 0

Solution:

According to the Avogadro's number:  

6.022 *10^23 drops per 0.050 g/ drop = 3.011 *10^22 grams per mole of drops  

3.011 *10^22 grams per 1 kg / 1000 grams = 3.011 *10^19 kilograms / mole of drops  

thus the answers are:  

3.0 *10^22 grams per mole of drops  

3.0 *10^19 kilograms per mole of drops  

And,

In the calculation of how many moles of raindrops in the Pacific Ocean is:  

7.08X10^20kg per 3.0 *10^19 kilograms per mole of drops = 23.5 moles of drops

This is the required solution.  


Ahat [919]2 years ago
7 0

Raindrops vary in size from about 0.02 in. (0.5 mm) to as much as 0.33 in. (8 mm) in thunderstorms. Raindrops come in many different sizes and can get to as big as a quarter inch. They cannot get bigger than that and the reason is that the wind resistance begins breaking them up into smaller raindrops. Raindrops don't get much larger than a quarter inch

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If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is____J.
astra-53 [7]

Answer:If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is 15J.

If the kinetic energy of the ball decreases, then the potential energy will Increase.

Explanation:

5 0
2 years ago
5. A Dumas bulb is filled with chlorine gas at the ambient pressure and is found to contain 7.1 g of chlorine when the temperatu
kati45 [8]

Answer:

a. The original temperature of the gas is 2743K.

b. 20atm.

Explanation:

a. As a result of the gas laws, you can know that the temperature is inversely proportional to moles of a gas when pressure and volume remains constant. The equation could be:

T₁n₁ = T₂n₂

<em>Where T is absolute temperature and n amount of gas at 1, initial state and 2, final states.</em>

<em />

<em>Replacing with values of the problem:</em>

T₁n₁ = T₂n₂

X*7.1g = (X+300)*6.4g

7.1X = 6.4X + 1920

0.7X = 1920

X = 2743K

<h3>The original temperature of the gas is 2743K</h3><h3 />

b. Using general gas law:

PV = nRT

<em>Where P is pressure (Our unknown)</em>

<em>V is volume = 2.24L</em>

<em>n are moles of gas (7.1g / 35.45g/mol = 0.20 moles)</em>

R is gas constant = 0.082atmL/molK

And T is absolute temperature (2743K)

P*2.24L = 0.20mol*0.082atmL/molK*2743K

<h3>P = 20atm</h3>

<em />

7 0
2 years ago
Carbon dating of small bits of charcoal used in cave paintings has determined that some of the paintings are from 10000 to 30000
Andru [333]

The age of painting was determined from the decay kinetics of the radioactive Carbon -14 present in the painting sample.

Given that the half life of Carbon-14 is 5730 years.

Radioactive decay reactions follow first order rate kinetics.

Calculating the decay constant from half life:

λ= \frac{0.693}{t_{1/2} }

        = \frac{0.693}{5730 yr} = 1.21*10^{-4}yr^{-1}

Setting up the radioactive rate equation:

ln\frac{A_{t} }{A_{0} } =-kt

Where A_{t} = Activity after time t = 0.80microCi

A_{t} = initial activity = 6.4microCi

k = decay constant = 1.21*10^{-4}yr^{-1}

ln\frac{0.80uCi}{6.4uCi} =-(1.21*10^{-4}yr^{-1})t

ln 0.125 = -(1.21*10^{-4}yr^{-1})t

-2.079=-(1.21*10^{-4}yr^{-1})t

t=\frac{2.07944}{1.21*10^{-4} } yr

 = 17185 years

t = 17185 years

Therefore age of the painting based in the radiocarbon -14 dating studies is 17185 years



6 0
2 years ago
Write an equation for the formation of bf3(g) from its elements in their standard states.
blagie [28]
In nature, boron is monoatomic. Therefore, its formula is B.
On the other hand, fluorine is diatomic. Therefore, its formula is F2

Now, the basic unbalanced equation is:
B + F2 .........> BF3

Now, we need to balance this equation. As you can see, we have two fluorine moles entering the reaction and 3 formed in the products.
Balancing the equation, we will reach the following balanced reaction:
2B + 3F2 .......> 2BF3 
7 0
2 years ago
Suppose that on a hot and sticky afternoon in the spring, a tornado passes over the high school. If the air pressure in the lab
uranmaximum [27]

The answer is B) 230 m3

5 0
2 years ago
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