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2 years ago

How many moles of ions are in 1.45 mol of K2SO4 ?

Chemistry

1 answer:

leonid [27]2 years ago

3 0

Answer:

Explanation:

First we look generally at what makes K2SO4.

In one mole of K2SO4, there are 2 moles of the potassium ion (K+) and 1 mole of sulfate ion (SO4 2-).

Knowing that; in 1.75 moles of K2SO4, there must be 2 x 1.75moles of potassium ion (K+) and 1 x 1.75moles of Sulfate ion (SO4 2-)

This gives us 3.5moles of K+ and 1.75moles of SO4 2-

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Which of the following actions cannot induce voltage in a wire?

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The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54.8. A reaction vessel contains 0.0890 M H

Mars2501 [29]

Answer: The reaction is not at equilibrium and will proceed to make more products to reach equilibrium.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

K is the constant of a certain reaction when it is in equilibrium, while Q is the reaction quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

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The expression for $Q$ is written as:

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$Q=0.074$

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Thus as $Q$ , the reaction will shift towards the right i.e. towards the product side.

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2 years ago

Which of the following are examples of plasma?

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A precipitate forms when mixing solutions of sodium fluoride (NaF) and lead II nitrate (Pb(NO3)2). Complete and balance the net

Margarita [4]

Answer:

Pb^2+(aq) + 2F-(aq) → PbF2(s)

Explanation:

Step 1: Data given

sodium fluoride = NaF

lead(II)nitrate Pb(NO3)2

Step 2: The unbalanced equation

NaF(aq) + Pb(NO3)2(aq) → PbF2(s) + NaNO3(aq)

Step 3: Balancing the equation

NaF(aq) + Pb(NO3)2(aq) → PbF2(s) + NaNO3(aq)

On the left side we have 2x NO3 (in Pb(NO3)2), on the right side we have 1x NO3 (in NaNO3). To balance the amount of NO3 we hvae to multiply NaNO3 on the right side by 2.

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Step 4: Calculate net ionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

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Pb^2+(aq) + 2F-(aq) → PbF2(s)

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2 years ago