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lilavasa [31]
1 year ago
13

The following reaction is exothermic. C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g)C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g) Predict the effect (shi

ft right, shift left, or no effect) of increasing and decreasing the reaction temperature. You may want to reference (Pages 665 - 672) Section 15.9 while completing this problem. Part A Predict the effect (shift right, shift left, or no effect) of increasing the reaction temperature.
Chemistry
1 answer:
swat321 year ago
6 0

Answer:

I) increasing the reaction temperature shift equilibrium left

II) decreasing the reaction temperature equilibrium right

Explanation:

The equation C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g) represent cellular respiration where glucose is oxidized by oxygen to yeild carbon dioxide and water respectively. Also energy is released to drive cellular processes.

Since, cellular respiration is an exothermic reaction:

- increasing the reaction temperature shift equilibrium to left favoring the reactants, glucose and oxygen production

- decreasing the reaction temperature shift equilibrium to right favoring the products, carbon dioxide and water production

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At 4.00 L, an expandable vessel contains 0.864 mol of oxygen gas. How many liters of oxygen gas must be added at constant temper
fgiga [73]

Answer:

We have to add 2.30 L of oxygen gas

Explanation:

Step 1: Data given

Initial volume = 4.00 L

Number of moles oxygen gas= 0.864 moles

Temperature = constant

Number of moles of oxygen gas increased to 1.36 moles

Step 2: Calculate new volume

V1/n1 = V2/n2

⇒V1 = the initial volume of the vessel = 4.00 L

⇒n1 = the initial number of moles oxygen gas = 0.864 moles

⇒V2 = the nex volume of the vessel

⇒n2 = the increased number of moles oxygen gas = 1.36 moles

4.00L / 0.864 moles = V2 / 1.36 moles

V2 = 6.30 L

The new volume is 6.30 L

Step 3: Calculate the amount of oxygen gas we have to add

6.30 - 4.00 = 2.30 L

We have to add 2.30 L of oxygen gas

4 0
2 years ago
What happens when Ammonia reacts with zinc sulphate solution
Ratling [72]
It will form a tetraamminezinc sulphate and a blue solution will be formed...the reaction should be carried out in a fume chamber because a poisonous substance will be released to the atmosphere
3 0
1 year ago
The electron configuration of an element is 1s22s22p4. Describe what most likely happens when two atoms of this element move tow
ahrayia [7]

When two atoms of this element move towards each other, they will combine in a covalent bond to form a diatomic molecule.

Looking at the electron configuration of the atoms; 1s2 2s2 2p4, we can see that these are atoms of elements in group 16. The elements in group 16 has a general outer electronic configuration of ns2np4. They have a valency of 2.

When two atoms of this element approach each other, they will combine in a covalent bond to form a compound. If this element is depicted as X, the compound formed is X2.

Learn more: brainly.com/question/1527403

5 0
1 year ago
Soda drinks bubble when the bottle is opened because:
mihalych1998 [28]

Answer:

(3) the partial pressure of carbon dioxide above the solution is reduced.

Explanation:

We know , Soda water contains pressured carbon dioxide pressured with cap because we know according to Henry's law partial pressure of the gas is directly proportional to pressure applied. Therefore, CO_2 is pressurized in the bottle.

But as we open the bottle the pressure decreases the excess CO_2 (and air) escapes producing effervescence and partial pressure of CO_2 decreases. ( Because of Henry's Law)  

Hence, it is the required solution.

7 0
2 years ago
If the lead can be extracted with 92.5% efficiency, what mass of ore is required to make a lead sphere with a 3.50 cm radius? le
ElenaW [278]

The volume of sphere can be calculated using the following formula:


V=\frac{4}{3}\pi r^{3}


Here, r is radius of the sphere which is 3.5 cm. Putting the value,


V=\frac{4}{3}\pi r^{3}=\frac{4}{3}(3.14)(3.5cm)^{3}=180 cm^{3}


This is equal to the volume of lead, density of lead is 11.34 g/cm^{3} thus, mass of lead can be calculated as follows:


m=d×V


Putting the values,


m=11.34 g/cm^{3}\times 180 cm^{3}=2041.2 g


Let the mass of ore be 1 g, 68.6% of galena is obtained by mass, thus, mass of galena obtained will be 0.686 g.


Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:


m=0.686×0.866=0.5940 g


Therefore, 0.5940 g of lead is obtained from 1 g of ore for 100% efficiency, thus, for 92.5% efficiency

m=\frac{92.5}{100}\times 0.5940=0.54945 g

1 g of lead obtain from\frac{1}{0.54945}=1.82 grams of ore.


Thus, 2041.2 g of lead obtain from:


2041.2\times 1.82=3.715\times 10^{3}g or 3.715 kg


Therefore, mass of ore required to make lead sphere is 3.715 kg.


6 0
2 years ago
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