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lilavasa [31]
2 years ago
13

The following reaction is exothermic. C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g)C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g) Predict the effect (shi

ft right, shift left, or no effect) of increasing and decreasing the reaction temperature. You may want to reference (Pages 665 - 672) Section 15.9 while completing this problem. Part A Predict the effect (shift right, shift left, or no effect) of increasing the reaction temperature.
Chemistry
1 answer:
swat322 years ago
6 0

Answer:

I) increasing the reaction temperature shift equilibrium left

II) decreasing the reaction temperature equilibrium right

Explanation:

The equation C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g) represent cellular respiration where glucose is oxidized by oxygen to yeild carbon dioxide and water respectively. Also energy is released to drive cellular processes.

Since, cellular respiration is an exothermic reaction:

- increasing the reaction temperature shift equilibrium to left favoring the reactants, glucose and oxygen production

- decreasing the reaction temperature shift equilibrium to right favoring the products, carbon dioxide and water production

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irina1246 [14]
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2 years ago
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OverLord2011 [107]

Answer : The number of moles of oxygen present in a sample are 11.3 moles.

Explanation :

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Or we can say that, 1 mole of of Ni(CO)_4 has 1 mole of nickel (Ni), 4 moles of carbon (C) and 4 moles of oxygen.

That means,

Number of moles of carbon = Number of moles of oxygen

As we are given that:

Number of moles of carbon = 11.3 moles

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7 0
2 years ago
You are asked to determine the mass of a piece of copper using its reported density, 8.96 g/ml, and a 150-ml graduated cylinder.
kakasveta [241]

Answer:- Mass of copper piece is 290 gram.

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density of copper is given as 8.96 gram per mL.

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Let's multiply the volume by density to calculate the mass of copper:

mass of copper = 32mL(\frac{8.96g}{mL})

mass of copper = 286.72 g

Volume has two significant figures, so if we round the mass to two significant figures then it becomes 290 g.

7 0
2 years ago
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For the reaction n2(g) + 2h2(g) â n2h4(l), if the percent yield for this reaction is 77.5%, what is the actual mass of hydrazine
Rudiy27

First calculate the moles of N2 and H2 reacted.

moles N2 = 27.7 g / (28 g/mol) = 0.9893 mol

moles H2 = 4.45 g / (2 g/mol) = 2.225 mol

 

We can see that N2 is the limiting reactant, therefore we base our calculation from that.

Calculating for mass of N2H4 formed:

mass N2H4 = 0.9893 mol N2 * (1 mole N2H4 / 1 mole N2) * 32 g / mol * 0.775

<span>mass N2H4 = 24.53 grams</span>

7 0
2 years ago
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2 years ago
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