<u>Answer:</u> This illustrates law of conservation of mass.
<u>Explanation:</u>
Dalton's theory is based on mainly two laws which are law of conservation of mass and law of constant proportion.
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The chemical equation for the decomposition of calcium carbonate follows:

We are given:
Mass of calcium carbonate = 100 grams
Mass of calcium oxide = 56 grams
Mass of carbon dioxide = 44 grams
Total mass on reactant side = 100 g
Total mass on product side = 56 + 44 = 100 g
As, the total mass on reactant side is equal to the total mass on product side.
Thus, this illustrates law of conservation of mass.
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Answer:
The answer to be filled in the respective blanks in question is
3 and 1
Explanation:
So, we know that the formation of cabon-dioxide mole and that of Adenosin-Tri-Phosphate (ATP) moles will be in the ratio of 3:1 i.e., three carbon-di-oxide moles and 1 ATP mole.
Therefore, we can say that one pyruvate mole when passed through citric acid cycle and pyruvate dehydrogenase yields carbon-di-oxide and ATP moles in the ratio 3:1
Answer:
The average kinetic energy of the gas particles is greater in container B because it has a higher temperature.
Explanation:
<em>The correct option would be that the average kinetic energy of the gas particles is greater in container B because it has a higher temperature.</em>
<u>According to the kinetic theory of matter, the temperate of a substance is a measure of the average kinetic energy of the molecules of substance. In other words, the higher the temperature of a substance, the higher the average kinetic energy of the molecules of the substance.</u>
In the illustration, the gas in container B showed a higher temperature than that of container A as indicated on the thermometer, it thus means that the average kinetic energy of the molecules of gas B is higher than those of gas A.