Which term names the metamorphic change to a rock that results mainly from the heat energy of nearby magma? A. local metamorphis
2 answers:
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Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.
Explanation : As a single egg cell has an approximately diameter of 100 μm.
We can use this formula to calculate area of the cell membrane;
A = π ;
We can take π as 3.14 and we get;
A = 3.14 X
Soving we get;
A = 7850 μ
Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μ but;
here 1 μ = 7850 μ
dye molecules.
Therefore, 10 fluorescent molecules will need;
7850 X 10 = 78500 molecules of dye.
Therefore, the answer is 78500 molecules of dye.
The given question is incomplete. The complete question is given here :
The equilibrium constant for the reaction is M.
This value indicates that
A. is a stronger base than
B. HCN is a stronger acid than HONO
C. The conjugate base of HONO is
D. The conjugate acid of CN- is HCN
Answer: A. is a stronger base than
Explanation:
Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.
When ; the reaction is product favoured.
When ; the reaction is reactant favored.
; the reaction is in equilibrium.
As, , the reaction will be product favoured and as it is a acid base reaction where
acts as acid by donating
ions and
acts as base by accepting
Thus is a strong acid thus
will be a weak conjugate base and
is a strong base which has weak
conjugate acid.
Thus the high value of K indicates that is a stronger base than
Answer:
3.69 g
Explanation:
Given that:
The mass m = 325 g
The change in temperature ΔT = ( 1540 - 165)° C
= 1375 ° C
Heat capacity = 0.490 J/g°C
The amount of heat required:
q = mcΔT
q = 325 × 0.490 × 1375
q = 218968.75 J
q = 218.97 kJ
The equation for the reaction is expressed as:
Then,
1 mole of the ethyne is equal to 26 g of ethyne required for 1544 kJ heat.
Thus, for 218.97 kJ, the amount of ethyne gas required will be:
= 3.69 g