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Fofino [41]
1 year ago
9

Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide in part 1. In part 2

answer the question about the transformation.

Chemistry
2 answers:
ipn [44]1 year ago
5 0

Answer:

The major product formed is a benzyl allyl compound, namely 2-methylene propylbenzene

Explanation:

<u>Part 1.</u>

The product formed from this Wittig reaction with phosphonium ylide is a phenylallyl compound, 2-methylene propylbenzene. Structure and reaction synthesis is attached in file.

<u>Part 2</u>

The types of transformation involved are:

  • alkylation (as there is a transfer of alkyl group)
  • addition (reaction of ylide)

Ilia_Sergeevich [38]1 year ago
4 0

Answer:

2-methylene propylbenzene (major product)

Explanation:

This reaction yields olefins and organophosphorus compound and is also known as wittig olefination. The reactants fits the category of a ketone (1-phenylpropan-1-one) and a Wittig reagent (phosphonium ylide).

Part 1: Answer in the fig. Below.

1-phenylpropan-1-one + phosphonium ylide ➡ phenylallyl compound + 2-methylene propylbenzene (major product)

Part 2.

Classical mechanisms that happened during its transformation are thus;

• nucleophilic addition

• Elimination

• cycloaddition

• [2+2]/retro-[2+2] mechanism.

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An organic acid is composed of carbon (45.45%), hydrogen (6.12%), and oxygen (48.44%). Its molar mass is 132.12 g/mol. Determine
Andreas93 [3]

Answer:

C4H8O4

Explanation:

To determine the molecular formula, first, let us obtain the empirical formula. This is illustrated below:

From the question given, we obtained the following information:

C = 45.45%

H = 6.12%

O = 48.44%

Divide the above by their molar mass

C = 45.45/12 = 3.7875

H = 6.12/1 = 6.12

O = 48.44/16 = 3.0275

Divide by the smallest

C = 3.7875/3.0275 = 1

H = 6.12/3.0275 = 2

O = 3.0275/3.0275 = 1

The empirical formula is CH2O

The molecular formula is given by [CH2O]n

[CH2O]n = 132.12

[12 + (2x1) + 16]n = 132.12

30n = 132.12

Divide both side by the coefficient of n i.e 30

n = 132.12/30 = 4

The molecular formula is [CH2O]n = [CH2O]4 = C4H8O4

7 0
2 years ago
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At 73.0 ∘c , what is the maximum value of the reaction quotient, q, needed to produce a non-negative e value for the reaction so
damaskus [11]
Here we will use the general formula of Nernst equation:

Ecell = E°Cell - [(RT/nF)] *㏑Q

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E°Cell is standard state cell potential = - 0.87 V

and R is a constant = 8.314 J/mol K

and T is the temperature in Kelvin = 73 + 273 = 346 K

and F is Faraday's constant = 96485 C/mole

and n is the number of moles of electron transferred in the reaction=2  

and Q is the reaction quotient for the reaction 
SO42-2(aq) + 4H+(aq) +2Br-(aq) ↔  Br2(aq) + SO2(g) +2H2O(l)

so by substitution :

0 = -0.87 - [(8.314*346K)/(2* 96485)*㏑Q      → solve for Q 


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6 0
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Identify Earth’s neighbors in the solar system by choosing the correct answer. The are bodies of rock or gas that are named for
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Answer: The are bodies of rock or gas that are named for ancient gods.

Explanation:

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VENUS is the second planet in our solar system. It is named after the Roman goddess of love and beauty.

MARS is the fourth planet in our solar system. It is named after the Roman goddess of war.

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A student hears in chemistry class that a certain object is made of a pure substance. What can the student conclude about the ob
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2 attempts left select the single best answer. The radii of the lithium and magnesium ions are 76 pm and 72 pm, respectively. Wh
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The ionic character of any compound depend on the lattice energy as well as the electronegativity of element present in that compound.

More would be the lattice energy more would be ionic nature of that compound.

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In given case the ionic radii of oxide in both oxides would be equal therefore the lattice energy only depend on the ionic radii of cation.

Lattice energy (U)     =   \frac{1}{Ionic radii}

As the radii of Magnesium less then radii of lithium therefore lattice energy of Magnesium oxide would be more than lithium oxide.

Hence, MgO would be more ionic in nature than Li_{2}O

8 0
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