<span>(19.55 mol Au) / ( 1 ) x (196.97 g Au) / ( 1 mol Au) =
19.55 x 196.97 =
3850.76 g Au
I hope this helps you and have a great day!! :)
</span>
Answer:
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Explanation:
First balance the chemical equation:
⇄ 
two components are solid so these two will not exert any kind of pressure in the container so at equilibrium only CO2 will apply pressure on the container
Therefore only partial pressure of CO2 will be taken for the calculation of equilibrium pressure constant i.e. Kp
![K_p=[CO_2]](https://tex.z-dn.net/?f=K_p%3D%5BCO_2%5D)
![[CO_2]=p](https://tex.z-dn.net/?f=%5BCO_2%5D%3Dp)



<u>Answer:</u>
1. In Glucose: C : H : O = 1 : 2 : 1
2. In Sulfuric acid: H : S : O = 2 : 1 : 4
3. In Butene: C : H = 1 : 2
<u>Explanation:</u>
Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.
- In Glucose,

Moles of Carbon atom = 6
Moles of Hydrogen atom = 12
Moles of Oxygen atom = 6
Mole ratio of the atoms: C : H : O :: 6 : 12 : 6
Making this, the simplest mole ratio C : H : O = 1 : 2 : 1
- In Sulfuric acid,

Moles of Sulfur atom = 1
Moles of Hydrogen atom = 2
Moles of Oxygen atom = 4
Mole ratio of the atoms: H : S : O = 2 : 1 : 4
- In Butene,

Moles of Carbon atom = 4
Moles of Hydrogen atom = 8
Mole ratio of the atoms: C : H = 1 : 2
First step is to balance the reaction equation. Hence we get
P4 + 5 O2 => 2 P2O5
Second, we calculate the amounts we start with
P4: 112 g = 112 g/ 124 g/mol – 0.903 mol
O2: 112 g = 112 g / 32 g/mol = 3.5 mol
Lastly, we calculate the amount of P2O5 produced.
2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4
mol of P2O5.
This is 1.4 * (31*2 + 16*5) = 198.8 g