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Nikitich [7]
2 years ago
7

Which of the following steps correctly converts 6 grams of fluorine to an equivalent number of moles of fluorine?

Chemistry
2 answers:
Tasya [4]2 years ago
6 0

Answer:

i can confirm that this is correct^

Explanation:

kati45 [8]2 years ago
4 0

Answer:

Divide 6 grams by the atomic mass of fluorine.

Explanation:

Number of moles = Mass / atomic mass of fluorine

Given data:

Mass of fluorine = 6 g

How to convert into moles of fluorine = ?

Solution:

Number of moles = Mass / atomic mass of fluorine

Number of moles = 6 g/  19 g/mol

Number of moles =  0.32 mol

So in order to convert the 6 g of fluorine into moles we have to divide the 6 by atomic mass of fluorine.

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These little bunnies (A, B, and C) were born in the same litter to the same parents, but they have different traits for the feat
marta [7]

Answer:

Due to random assortment and incomplete dominance of alleles.

Explanation:

The bunnies end up with ear thicknesses that are different from one another due to random assortment of alleles during gamete formation according to Mendel.

In addition to random assortment, the allele for thick ear also displayed what is known as incomplete dominance over the allele for thin ear to arrive at an average ear thickness.

3 0
2 years ago
Water at 4.4°C is to flow through a horizontal, commercial steel pipe having a length of 305 m at the rate of 150 gal/min. If a
Pavel [41]

Answer:

d = 70.5 mm

Explanation:

given,

length of pipe = 305 m

discharge rate = 150 gal/min

pipe diameter = ?

1 gal/min = 6.30902 ×  10⁻⁵ m³/s

150 gal/min = 150 × 6.30902 ×  10⁻⁵ m³/s

                   = 9.46 × 10⁻³ m³/s

h = \dfrac{flv^2}{2gd}

h = \dfrac{flv^2}{2gd}

Q = A V

h = \dfrac{fl(\dfrac{Q}{A})^2}{2gd}

h = \dfrac{fl(\dfrac{Q}{\dfrac{\pi}{4}d^2})^2}{2gd}

h= \dfrac{8flQ^2}{\pi^2gd^5}

f = 0.048 from moody chart using P/D = 0.00015

\dfrac{1}{d^5}= \dfrac{6.1\times \pi^2\times 9.8}{8\times 0.048\times 305\times 0.00946^2}

d = 70.5 mm

Diameter of the pipe is equal to 70.5 mm

7 0
2 years ago
1. Suppose 1.00 g of NaOH is used to prepare 250 mL of an NaOH solution. Compare the expected molarity of this solution to the a
geniusboy [140]

Answer:

0.1M solution of NaOH

Explanation:

1 mole of NaOH - 40g

? moles - 1 g = 1/40 = 0.025 moles.

Molarity of 1.00g of NaOH in 0.25L (250 mL) = no. of moles/volume

= 0.025/0.25

= 0.1M.

8 0
1 year ago
If a chemical reaction such as the formation of iron oxide contains 4 atoms of iron (fe) in the product how many atoms of iron (
inessss [21]
4. Number of atoms are conserved in chemical reactions
4 0
1 year ago
Read 2 more answers
For which of the following aqueous solutions would one expect to have the largest van’t Hoff factor (i)? a. 0.050 m NaCl b. 0.50
ira [324]

Answer:

The van't hoff factor of 0.500m K₂SO₄ will be highest.

Explanation:

Van't Hoff factor was introduced for better understanding of colligative property of a solution.

By definition it is the ratio of actual number of particles or ions or associated molecules formed when a solute is dissolved to the number of particles expected from the mass dissolved.

a) For NaCl the van't Hoff factor is 2

b) For K₂SO₄ the van't Hoff factor is 3 [it will dissociate to give three ions one sulfate ion and two potassium ions]

Out of 0.500m and 0.050m K₂SO₄, the van't hoff factor of 0.500m K₂SO₄ will be more.

c) The van't Hoff factor for glucose is one as it is a non electrolyte and will not dissociate.

7 0
2 years ago
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