Your answer is D. Since there is little to no magnetic field to wire, if it is copper which most wires are, there will be no voltage in a wire.
Answer:
A Reaction
3. Pt(NO₃)₂(aq) + Cu(s)
4. Cr(s) + H₂SO₄(aq)
B Non Reaction
1. Mn(s) + Ca(NO₃)₂(aq)
2. KOH(aq) + Fe(s)
Y > Q > W > Z > X
Explanation:
The first question is whether a reaction will occur base on the chemical equation below.
1. Mn(s) + Ca(NO₃)₂(aq)
2. KOH(aq) + Fe(s)
3. Pt(NO₃)₂(aq) + Cu(s)
4. Cr(s) + H₂SO₄(aq)
Firstly, some element are more reactive than others , base on this criteria element can be arranged base on it reactivity .
1. Mn(s) + Ca(NO₃)₂(aq)
This reaction will not occur because Mn cannot displace Ca in it compound. Usually, more reactive element displaces less reactive element.
2. KOH(aq) + Fe(s)
The reaction will not occur since Iron is less reactive and lower in the reactivity series than potassium . So iron won't be able to displace potassium.
3. Pt(NO₃)₂(aq) + Cu(s)
Copper is more reactive than platinum so it will displace platinum easily . The reaction will definitely occur.
4. Cr(s) + H₂SO₄(aq)
Chromium is higher up in the reactivity series than hydrogen so, it will definitely displace hydrogen in it compound . The reaction will occur in this case.
Base on the reaction
Q + W+ Reaction occurs
Since the reaction occurred element Q is more reactive as it displace element w from it compound.
X + Z+ No reaction
No reaction occurred because element x is less reactive than z therefore, it cannot displace z from it compound.
W + Z+ Reaction occurs
Element w is more reactive than z as it displaces z form it compound.
Q+ + Y Reaction occurs
Element Y is more reactive than element Q as it displaces Q from it compound.
Therefore, the order of reactivity from the most reactive to the least reactive will be Y > Q > W > Z > X
Answer:
It can be removed by acidic chemicals
Explanation:
Answer:
The answer to your question is 50 moles of O₂
Explanation:
Balanced Chemical reactions
1.- N₂(g) + 3H₂ (g) ⇒ 2NH₃ (g)
2.- 4NH₃ (g) + 5O₂(g) ⇒ 4NO (g) + 6H₂O (l)
moles of N₂(g) = 20 moles
moles of O₂(g) = ?
Process
1.- Calculate the moles of NH₃
1 mol of N₂ ------------- 2 moles of NH₃
20 moles of N₂ --------- x
x = (20 x 2) / 1
x = 40 moles of NH₃
2.- Calculate the moles of O₂
4 moles of NH₃ -------------- 5 O₂
40 moles of NH₃ ------------ x
x = (40 x 5) / 4
x = 200 / 4
x = 50 moles of O₂
