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strojnjashka [21]
2 years ago
13

Consider four beakers labeled A, B, C, and D, each containing an aqueous solution and a solid piece of metal. Identity the beake

rs in which a chemical reaction will occur and those in which no reaction will occur. Drag each item to the correct bin.
1. Mn(s) Ca(NO3)2(aq)
2. KOH(aq) Fe(s)
3. Pt(NO3)2(aq) Cu(s)
4. Cr(s) H2SO4(aq)
A. Reaction
B. Non-reaction
Consider the following data for five hypothetical element: Q, W, X, Y, and Z. Rank the elements from most reactive to least reactive.
Combination Observation of reaction
Q + W+ Reaction occurs
X + Z+ No reaction
W + Z+ Reaction occurs
Q+ + Y Reaction occurs
Place the element symbol from most to least reactive.
1. Q
2. W
3. X
4. Y
5. Z
A. Most reactive
B. Least reactive
Use the following reactions to arrange the elements A, B, C, and D in order of their rodox reactivity from most reactive to least reactive. Rank from most reactive to least reactive.
1. A + D+ righ tarrow A+ + D
2. C+ + D righ tarrow C + D+
3. B+ + D righ tarrow B + D+
4. B + C+ righ tarrow B+ + C
A. Most reactive
B. Least reactive
Chemistry
1 answer:
Anna71 [15]2 years ago
3 0

Answer:

A Reaction

3. Pt(NO₃)₂(aq) + Cu(s)

4. Cr(s) + H₂SO₄(aq)

B Non Reaction

1. Mn(s) + Ca(NO₃)₂(aq)

2. KOH(aq) +  Fe(s)

Y > Q > W > Z > X

Explanation:

The first question is whether a reaction will occur base on the chemical equation below.

1. Mn(s) + Ca(NO₃)₂(aq)

2. KOH(aq) +  Fe(s)

3. Pt(NO₃)₂(aq) + Cu(s)

4. Cr(s) + H₂SO₄(aq)

Firstly, some element are more reactive than others , base on this criteria element can be arranged  base on it reactivity .

1. Mn(s) + Ca(NO₃)₂(aq)

This reaction will not occur because Mn cannot displace Ca in it compound. Usually, more reactive element displaces less reactive element.

2. KOH(aq) +  Fe(s)

The reaction will not occur since Iron is less reactive and lower in the reactivity series than potassium . So iron won't be able to displace potassium.

3. Pt(NO₃)₂(aq) + Cu(s)

Copper is more reactive than platinum so it will displace platinum easily . The reaction will definitely occur.

4. Cr(s) + H₂SO₄(aq)

Chromium is higher up in the reactivity series than hydrogen so, it will definitely displace hydrogen in it compound . The reaction will occur in this case.

Base on the reaction

Q + W+ Reaction occurs

Since the reaction occurred element Q is more reactive as it displace element w from it compound.  

X + Z+ No reaction

No reaction occurred because element x is less reactive than z therefore, it cannot displace z from it compound.

W + Z+ Reaction occurs

Element w is more reactive than z as it displaces z form it compound.

Q+ + Y Reaction occurs

Element Y is more reactive than element  Q as it displaces Q from it compound.

Therefore, the  order of reactivity from the most reactive to the least reactive will be Y > Q > W > Z > X

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1 year ago
The oxidation numbers of nitrogen in NH3, HNO3, and NO2 are, respectively: -3, -5, +4 +3, +5, +4 -3, +5, -4 -3, +5, +4
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In NH3 , let oxidation number of N be x

x + (+1)3 = 0

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In HNO3 , let oxidation number of N be x

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What is the empirical formula for C2H4(OH)2??
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<span>Empirical formula for C2H4(OH)2  is</span><span>
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A mixture of Na2CO3 and MgCO3 of mass 7.63 g is reacted with an excess of hydrochloric acid. The CO2 gas generated occupies a vo
Svetlanka [38]

Answer:

58.6 % by mass of Na₂CO₃

Explanation:

This is the reaction:

Na₂CO₃  +  MgCO₃ +  4HCl  →  MgCl₂  +  2NaCl  + 2CO₂  +  2H₂O

Let's find out the moles of CO₂ produced, by the Ideal Gases Law

1.24 atm . 1.67 L = n . 0.082 . 299K

(1.24 atm . 1.67 L / 0.082 . 299K) = n

0.0844 moles = n

Ratio is 2:1, so 2 moles of dioxide were produced by 1 mol of sodium carbonate. Let's make a rule of three:

2 moles of CO₂ were produced by 1 mol of Na₂CO₃

Then, 0.0844 moles of Co₂ would beeen produced by (0.0844 .1)/2  = 0.0422 moles of Na₂CO₃.

Let's convert this moles into mass (mol . molar mass)

0.0422 mol . 106 g/mol = 4.47 g

Finally we can know the mass percent of sodium carbonate in the mixture

(Mass of compound /Total mass) . 100 → (4.47 g / 7.63g) . 100 = 58.6 %

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For the following equilibrium: A+2B⇋C+3D If the change in concentration for B is 0.44 M, what will be the change in concentratio
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Answer:0.22M

Explanation:

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