Your answer is D. Since there is little to no magnetic field to wire, if it is copper which most wires are, there will be no voltage in a wire.
Answer:
1.822 g of magnesium hydroxide would be produced.
Explanation:
Balanced reaction: 
Compound Molar mass (g/mol)
NaOH 39.997
95.211
58.3197
So, 2.50 g of NaOH =
mol of NaOH = 0.0625 mol of NaOH
4.30 g of
=
mol of
= 0.0452 mol of 
According to balanced equation-
2 mol of NaOH produce 1 mol of
So, 0.0625 mol of NaOH produce
mol of NaOH or 0.03125 mol of NaOH
1 mol of
produces 1 mol of
So, 0.0452 mol of
produce 0.0452 mol of
As least number of moles of
are produced from NaOH therefore NaOH is the limiting reagent.
So, amount of
would be produced = 0.03125 mol
=
g
= 1.822 g
Answer:
B. n-octyl alcohol and 1-octene
Explanation:
Thin-layer chromatography (TLC) is a chromatography technique used to separate non-volatile mixtures. The principle is that different compounds in the sample mixture travel at different rates due to the differences in interactions with stationary phase and due to the differences in solubility in the solvent. The principal chemical property for separation using this technique is molecular polarity
You can intuit than hexadecane and octadecane don't have big polarity differences, also chlorobenzene and bromobenzene haven't.
An alcohol as n-octyl alcohol has different polarity than an alkene as 1-octene.
Thus, using thin layer chromatography is most easy to separate:
<em>B. n-octyl alcohol and 1-octene
</em>
<em></em>
I hope it helps!
<em></em>
Answer:
PV=nRT
n = PV/RT
n = m/Mm
m/Mm = PV/RT
m = MmPV/RT
T in kelvin = T Celsius + 273.15 = 293.15 K
m = (26.04 x 1.39 x 55)/(0.08206 x 293.15)
mass in grams = 82.8 grams
Explanation:
Ideal gases formula is PV=nRT, where:
P is the pressure (1.39 atm in this case)
V is the volume (55.0 L in this case)
R is the gas constant (0.08206 L.atm/K.mole)
T is the temperature (20.0C) should be converted to Kelvin
all the unit should correspond to the one in the R.
we also know that to find the mass, we can use number mole with the formula number of mole(n) = mass (m) divided by the molar mass (Mm). therefore we substituted that in the formula and make (m) the subject of the formula.
we found the mass to be 82.8 grams