What is the limiting reactant for the following reaction given we have 3.4 moles of Ca(NO3)2 and 2.4 moles of Li3PO4?Reaction: 3
2 answers:
Answer:
The answer to your question is letter c. Ca(NO₃)₂
Explanation:
Data
Ca(NO₃)₂ = 3.4 moles
Li₃PO₄ = 2.4 moles
Reaction
3 Ca(NO₃)₂ + 2 Li₃PO₄ ⇒ 6 LiNO₃ + Ca₃(PO₄)₂
Process
Calculate the proportion theoretical and experimental of reactants and compare these proportions.
Theoretical proportion
Ca(NO₃)₂ / Li₃PO₄ = = 1.5
Experimental proportion
Ca(NO₃)₂ / Li₃PO₄ =
As the experimental proportion is lower than the theoretical proportion we conclude that the amount of Li₃PO₄ increased in the experiment so the limiting reactant is Ca(NO₃)₂.
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<u>Answer:</u> The volume of chlorine gas produced in the reaction is 2.06 L.
<u>Explanation:</u>
- <u>For potassium permanganate:</u>
To calculate the number of moles, we use the equation:
Given mass of potassium permanganate = 6.23 g
Molar mass of potassium permanganate = 158.034 g/mol
Putting values in above equation, we get:
- <u>For hydrochloric acid:</u>
To calculate the moles of hydrochloric acid, we use the equation:
Molarity of HCl = 6.00 M
Volume of HCl = 45.0 mL = 0.045 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
- For the reaction of potassium permanganate and hydrochloric acid, the equation follows:
By Stoichiometry of the reaction:
16 moles of hydrochloric acid reacts with 2 moles of potassium permanganate.
So, 0.27 moles of hydrochloric acid will react with = of potassium permanganate.
As, given amount of potassium permanganate is more than the required amount. So, it is considered as an excess reagent.
Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
16 moles of hydrochloric acid reacts with 5 moles of chlorine gas.
So, 0.27 moles of hydrochloric acid will react with = of chlorine gas.
- To calculate the volume of gas, we use the equation given by ideal gas equation:
where,
P = pressure of the gas = 1.05 atm
V = Volume of gas = ? L
n = Number of moles = 0.0843 mol
R = Gas constant =
T = temperature of the gas =
Putting values in above equation, we get:
Hence, the volume of chlorine gas produced in the reaction is 2.06 L.
Answer:
Explanation:
The number of molecules of KCN can be found by using the formula
<h3>N = n × L</h3>where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.00048 × 6.02 × 10²³
We have the final answer as
Hope this helps you