Question

A poisoned pill contains 0.00048 moles of KCN. How many molecules are in this sample?

Answer 1

Answer:

$2.89 \times {10}^{20} \: \: molecules$

Explanation:

The number of molecules of KCN can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.00048 × 6.02 × 10²³

We have the final answer as

$2.89 \times {10}^{20} \: \: \: molecules$

Hope this helps you