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inna [77]
2 years ago
6

Rank the size of a change in temperature of one degree Fahrenheit, one degree Celsius, and one kelvin. In other words, if a ther

mometer were to show that the temperature outside increased by these amounts, which change would feel the largest? If any of the options are the same magnitude, stack them above one another. Rank the sizes of one degree in each scale from largest to smallest. To rank items as equivalent, overlap them.
Chemistry
1 answer:
Lena [83]2 years ago
3 0
The relationship between Fahrenheit and Celsius is:

°F = 1.8*°C + 32

If we differentiate the given expression to find the relationship between a unit change of °F and °C, we get:
Δ°F = 1.8*Δ°C

This means that a change in 1 degree Fahrenheit is equivalent to a change of 1.8 degrees Celsius. Moreover, a one degree change in Fahrenheit is the same as a one-degree change on the Rankine scale, so, ranking the scales in order from higher change to lower change:

1) Fahrenheit = Rankine
2) Celsius = Kelvin
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The gaseous product of a reaction is collected in a 25.0-l container at 27
nataly862011 [7]
To find the number of moles of gas we can use the ideal gas law equation, we dont need to use the mass of gas given as we only have to find the number of moles 
PV = nRT 
P - pressure - 300.0 kPa 
V - volume - 25.0 x 10⁻³ m³
n - number of moles 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 27 °C + 273 = 300 K
substituting these values in the equation 
300.0 kPa x 25.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K 
n = 3.01 mol 
number of mols of gas - 3.01 mol
4 0
2 years ago
If 0.640 g of beautiful blue crystals of azulene is dissolve in 99 g of benzen, the resulting solutions boils at 80.23 degrees c
devlian [24]

This problem handles<em> boiling-point elevation</em>, which means we will use the formula:

ΔT = Kb * m

Where ΔT is the difference of Temperature between boiling points of the solution and the pure solvent (Tsolution - Tsolvent). Kb is the ebullioscopic constant of the solvent (2.64 for benzene), and m is the molality of the solution.

Knowing that benzene's boiling point is 80.1°C, we <u>solve for m</u>:

Tsolution - Tsolvent = Kb * m

80.23 - 80.1 = 2.64 * m

m = 0.049 m

We use the definition of molality to <u>calculate the moles of azulene</u>:

0.049 m = Xmoles azulene / 0.099 kgBenzene

Xmoles azulene = 4.87 x10⁻³ moles azulene

We use the mass and the moles of azulene to<u> calculate its molecular weight</u>:

0.640 g / 4.875 x10⁻³ mol = 130.28 g/mol

<em>A molecular formula that would fulfill that molecular weight</em> is C₁₀H₁₀. So that's the result of solving this problem.

The actual molecular formula of azulene is C₁₀H₈.

6 0
2 years ago
Alkenes: draw the product of 1-chloro-2-ethylcyclohexene with hydrogen gas and a platinum catalyst
atroni [7]
Reacting 1-chloro-2-ethylcyclohexene with hydrogen gas using a platinum catalyst would give a product of 1-chloro-2-ethylcyclohexane. 

Hydrogen gas is a reducing agent, which in this reaction, simply mean that the alkene double bond in the cyclohexene will disappear because one of the two bonds forming the double bond (in the alkene) will be connected to a hydrogen atom. The platinum catalyst is necessary to allow the reaction to proceed at a much lower (activation) energy than would have been required. 

7 0
2 years ago
The recommended daily allowance (rda of calcium is 1.2 g. calcium carbonate contains 12.0% calcium by mass. how many grams of ca
defon
1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!

2) Mass fraction of this is excessive data.

3) The solution is:

m(Ca)=1.2 g

m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)

m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
4 0
2 years ago
Read 2 more answers
A 75 lb (34 kg) boy falls out of a tree from a height of 10 ft (3 m). i. What is the kinetic energy of the boy when he hits the
Jobisdone [24]

Answer:

Kinetic energy of boy just before hitting the ground is \approx1000 J.

Speed of boy just before hitting the ground is 7.67 m/s

or 17.16 mi/hr.

Explanation:

Given that:

Mass of boy = 75lb = 34 kg

Height, h = 10ft = 3m

To find:

Kinetic energy of boy when he hits the ground.

<em>As per law of conservation of energy The potential energy gets converted to kinetic energy.</em>

<em></em>

<em></em>\therefore<em> </em>Kinetic energy at the time boy hits the ground = Initial potential energy of the boy when he was at the Height 'h'

The formula for potential energy is given as:

PE = mgh

Where m is the mass

g is the acceleration due to gravity, g = 9.8 m/s^2

h is the height of object

Putting all the values:

PE = 34 \times 9.8 \times 3 \approx 1000\ J

Hence, Kinetic energy is \approx1000 J.

Formula for Kinetic energy is:

KE = \dfrac{1}{2}mv^2

where m is the mass and

v is the speed

Putting the values and finding v:

1000 = \dfrac{1}{2}\times 34 \times v^2\\\Rightarrow v^2 = 58.82\\\Rightarrow v = 7.67\ m/s

Given that:

1 m = 1.094 yd and 1 mi = 1760 yd

\Rightarrow 1609\ m = 1\ mi

Converting 7.67 m/s to miles/hour:

\dfrac{7.67 \times 3600}{1609}=17.16\ mi/h

4 0
2 years ago
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