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inna [77]
2 years ago
6

Rank the size of a change in temperature of one degree Fahrenheit, one degree Celsius, and one kelvin. In other words, if a ther

mometer were to show that the temperature outside increased by these amounts, which change would feel the largest? If any of the options are the same magnitude, stack them above one another. Rank the sizes of one degree in each scale from largest to smallest. To rank items as equivalent, overlap them.
Chemistry
1 answer:
Lena [83]2 years ago
3 0
The relationship between Fahrenheit and Celsius is:

°F = 1.8*°C + 32

If we differentiate the given expression to find the relationship between a unit change of °F and °C, we get:
Δ°F = 1.8*Δ°C

This means that a change in 1 degree Fahrenheit is equivalent to a change of 1.8 degrees Celsius. Moreover, a one degree change in Fahrenheit is the same as a one-degree change on the Rankine scale, so, ranking the scales in order from higher change to lower change:

1) Fahrenheit = Rankine
2) Celsius = Kelvin
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A sample of oxygen gas was found to effuse at a rate equal to two times that of an unknown gas. what is the molar mass (in g/mol
inn [45]
<span>128 g/mol Using Graham's law of effusion we have the formula: r1/r2 = sqrt(m2/m1) where r1 = rate of effusion for gas 1 r2 = rate of effusion for gas 2 m1 = molar mass of gas 1 m2 = molar mass of gas 2 Since the atomic weight of oxygen is 15.999, the molar mass for O2 = 2 * 15.999 = 31.998 Now let's subsitute the known values into Graham's equation and solve for m2. r1/r2 = sqrt(m2/m1) 2/1 = sqrt(m2/31.998) 4/1 = m2/31.998 127.992 = m2 So the molar mass of the unknown gas is 127.992 g/mol. Rounding to 3 significant figures gives 128 g/mol</span>
4 0
2 years ago
If 10.0 grams of NaHCO3 is added to 10.0 g of HCl, determine the efficiency of baking soda as an antacid if 6.73 g of NaCl was p
Lapatulllka [165]

Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

The question ask us to calculate the percentage yield of NaCl.

The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

as

1 mole of NaHCO3 produces 1 mole of NaCl

Therefore,

molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g

molar mass of NaCl = 23 + 35.5 = 58.5 g

1 mole of NaHCO3 = 84 g

1 mole of NaCl  = 58.5 g

since 84 g of NaHCO3 produces 58.5 g of NaCl

10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

Theoretical yield of NaCl = (10 × 58.5)/84

Theoretical yield of NaCl = 585/84

Theoretical yield of NaCl  = 6.9642857143 g

percentage yield of NaCl = actual yield/theoretical yield × 100

percentage yield of NaCl = 6.73/6.9642857143 × 100

percentage yield of NaCl = 673/6.9642857143

percentage yield of NaCl = 96.635897436%

percentage yield of NaCl = 96.64%

3 0
2 years ago
Read 2 more answers
A 11.0 kg iron weightlifting plate has a volume of 1400 cm3 . What is the density of the iron plate in g/cm3?
qwelly [4]
The easy part about this question is that it already gives you the equation to use. If you're trying to find the weight in g/cm^3, all you have to do is divide the weight in grams (g) by the volume in cubic centimeters (cm^3).

The problem already gives you the volume, so you just need to convert kilograms (kg) into grams (g).

Hint: "kilogram" means 1000 grams. There are 1,000 grams in each kilogram.

So find the weight of the object in grams, then divide that number by the volume in cm^3.
5 0
2 years ago
Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?
Lena [83]

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

4 0
2 years ago
Calculate the number of grams of sulfuric acid in 1 gallon of battery acid if the solution has a density of 1.31 g/ml and is 37.
adoni [48]
<span>We know that density is equal to mass divided by volum, D=M/V and in this case we have 1 gallon of a solution of sulfuric acid with 37.4% of concentration in mass. 1 gallon is 3785.41 ml and according the formula M=D*V = 1.31 * 3785.41 = 4958.89 grams of solution. Only 37.4% of the solution is sulfuric acid, that is 4958.89 * 37.4/100= 1854.62 grams Then the number of grams of sulfuric acid is 1854.62 gr.</span>
7 0
2 years ago
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