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Alborosie
1 year ago
6

According to Valence Shell Electron Pair Repulsion (VSEPR) theory, which statement is correct? If a molecule has four pairs of e

lectrons, it will always have a tetrahedral structure. If a molecule is made up of three atoms, it will always have a linear structure. If a molecule is bent, it will always have unpaired electrons around the central atom. If a molecule has three atoms around a central atom, it will always be trigonal planar.
Chemistry
1 answer:
andrew11 [14]1 year ago
6 0

Answer: Option 1

Explanation: hopes it helps

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2. If a person in a wheelchair wanted to get to the second story of a two-story building, would it be easier to
katen-ka-za [31]

Answer:

The short steep ramp would be much harder because you will have to work more against gravity.

Explanation:

7 0
2 years ago
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Suppose that a certain fortunate person has a net worth of $79.0 billion ($7.90×1010). If her stock has a good year and gains $3
mario62 [17]
A net worth: $79.0 billion.
Value of stock : $3.20 billion.
New net worth:
$79.0 + $3.20 = $82.20 billion = $82.20 * 10^9 = $8.20 * 10^10
7 0
2 years ago
A laboratory utilizes a mixture of 10% dimethyl sulfoxide (DMSO) in the freezing and long-term storage of embryonic stem cells.
Mars2501 [29]

Answer:

The correct answer is "1.0100".

Explanation:

Let the volume of mixture be 100 ml.

then,

The volume of DMSO will be 10 mL as well as that of water will be 90 mL.

DMSO will be:

= 10\times 1.1004

= 11.004 \ g

The total mass of mixture will be:

= 90+11.004

= 101.004 \ g

Density of mixture will be:

= \frac{Mass}{Volume}

= \frac{101.004}{100}

= 1.01004 \ g/mL

hence,

Specific gravity of mixture will be:

= \frac{Density \ of \ mixture}{Density \ of \ water}

= \frac{1.01004}{1}

= 1.0100

3 0
2 years ago
For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomas
jolli1 [7]

Answer:

4,25% v/v H3PO4

Explanation:

The concentration of phosphoric acid (H3PO4) is expressed as a volume / volume percentage, which means:

%v/v H3PO4 = (mL of pure H3PO4/mL of solution)*100%

In other words, <u>we are only interested in the final volume of the solution to which the phosphoric acid was diluted, regardless of its composition</u>. Which in this case is 1 L (1000 mL).

We can then apply the following equation, commonly used to calculate the initial or final concentration (or volume) of a substance when it is diluted:

Ci*Vi=Cf*Vf

<u>Where</u>:

Ci, is the initial concentration of the substance.

Vi, the initial volume of the substance

Cf, the final concentration reached after dilution

Vf, the final volume of the solution at which the substance was diluted

In this case, the incognite would be the final concentration of H3PO4 reached after dilution, that is, Cf. Therefore, we proceed to clear Cf from the previous equation and replace our data:

Cf = (Ci*Vi)/Vf = (85% v/v * 50 mL)/1000 mL = 4,25 % v/v

Note that being up and down in the division, the mL unit is canceled to result in% v / v.

7 0
2 years ago
Carbon dating of small bits of charcoal used in cave paintings has determined that some of the paintings are from 10000 to 30000
Andru [333]

The age of painting was determined from the decay kinetics of the radioactive Carbon -14 present in the painting sample.

Given that the half life of Carbon-14 is 5730 years.

Radioactive decay reactions follow first order rate kinetics.

Calculating the decay constant from half life:

λ= \frac{0.693}{t_{1/2} }

        = \frac{0.693}{5730 yr} = 1.21*10^{-4}yr^{-1}

Setting up the radioactive rate equation:

ln\frac{A_{t} }{A_{0} } =-kt

Where A_{t} = Activity after time t = 0.80microCi

A_{t} = initial activity = 6.4microCi

k = decay constant = 1.21*10^{-4}yr^{-1}

ln\frac{0.80uCi}{6.4uCi} =-(1.21*10^{-4}yr^{-1})t

ln 0.125 = -(1.21*10^{-4}yr^{-1})t

-2.079=-(1.21*10^{-4}yr^{-1})t

t=\frac{2.07944}{1.21*10^{-4} } yr

 = 17185 years

t = 17185 years

Therefore age of the painting based in the radiocarbon -14 dating studies is 17185 years



6 0
2 years ago
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