The compound that could serve as a reactant in the neutralization reaction is H2SO4
Explanation
Neutralization reaction occur between an acids and a base. H2SO4 ( sulfuric acid) is a strong acid. It can be neutralized by strong base such as NaOH ( sodium hydroxide)
Example of neutralization reaction is
2NaOH + H2SO4 → Na2SO4 + 2H2O
Answer:
See explanation
Explanation:
Hydrogen has a valency of +1 or -1. Its electronic configuration is 1s1.
The 1s sub-level (first shell) is known to hold two electrons. This means that hydrogen may either loose this one electron in the 1s level to yield H^+ or accept another electron into this 1s level to form H^- (the hydride ion).
The formation of the hydride ion completes the 1s orbital.
The First Ionization energy of Nitrogen is greater (Not smaller)than that of Phosphorous. This is because going down the group (N and P are in same group) the number of shells increases, the distance of valence electrons from Nucleus increases and hence due to less interaction between nucleus and valence electrons it becomes easy to knock out the electron.
<span>The second ionization energy of Na is larger than that of Mg because after first loss of electron Na has gained Noble Gas Configuration (Stable Configuration) and now requires greater energy to loose both second electron and Noble Gas Configuration. While Mg after second ionization attains Noble Gas Configuration hence it prices less energy.</span>
Answer:
0.192 mol.
Explanation:
- To calculate the no. of moles of a substance (n), we use the relation:
<em>n = mass / molar mass.</em>
mass of AsH₃ = 15.0 g.
molar mass of AsH₃ = 77.95 g/mol.
∴ The number of moles in 15.0 g AsH₃ = mass / molar mass = (15.0 g) / (77.95 g/mol) = 0.192 mol.
