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1 year ago

In an experiment, 170.9 g of C2H4 was reacted with an excess of O2, 164.1 g of CO2 is produced.

Chemistry

1 answer:

jonny [76]1 year ago

7 0

Answer:

$Y=30.6\%$

Explanation:

Hello,

In this case, given the reaction, the molar mass of ethene is 28 g/mol and the molar mass of carbon dioxide is 44 g/mol. With that information we compute the theoretical yield considering a 1:2 molar ratio respectively between them:

$m_{CO_20}^{theoretical}=170.9gC_2H_4*\frac{1molC_2H_4}{28gC_2H_4}*\frac{2molCO_2}{1molC_2H_4} *\frac{44gCO_2}{1molCO_2} =537.1gCO_2$

Thus, we compute the percent yield with the given grams of carbon dioxide:

$Y=\frac{m_{CO_2}^{real}}{m_{CO_2}^{theoretical}}*100 \% =\frac{164.1g}{537.1gCO_2} *100 \%\\\\Y=30.6\%$

Regards.

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A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of water is 4.18 J•g^-1•C^-1. By how much will it’s temp

MrMuchimi

Answer: The temperature rise is $0.53^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g (1kg=1000g)

c = heat capacity of water = $4.18J/g^0C$

Initial temperature = $T_i$

Final temperature = $T_f$

Change in temperature , $\Delta T=T_f-T_i=?$

Putting in the values, we get:

$5280J=2400g\times 4.18J/g^0C\times \Delta T$

$\Delta T=0.53^0C$

Thus the temperature rise is $0.53^0C$

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2 years ago

All of the following reactions can be described as displacement reactions except:____________.

Lady_Fox [76]

Answer:

Explanation:

The reaction that is not a displacement reaction from all the options is $C_6H_6_{(l)} + Cl_{2(g)} --> C_6H_5Cl_{(l)} + HCl_{(g)}$

In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.

<em>Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.</em>

Correct option = b.

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2 years ago

Naomi is investigating the properties of a solid material. It takes 120 joules to raise the temperature of 10 grams of the mater

MrRissso [65]

When heat energy is supplied to a material it can raise the temperature of mass of the material.
Specific heat is the amount of energy required by 1 g of material to raise the temperature by 1 °C.
equation is
H = mcΔt
H - heat energy
m - mass of material
c - specific heat of the material
Δt - change in temperature
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c = 2.4 Jg⁻¹°C⁻¹

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2 years ago

HA and HB are two strong monobasic acids. 25.0cm3 of 6.0mol/dm3 HA is mixed with 45.0cm3 of 3.0mol/dm3 HB.

Lostsunrise [7]

Answer:

The H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

(Option C)

Explanation:

Given;

concentration of HA, $C_A$ = 6.0mol/dm³

volume of HA, $V_A$ = 25.0cm³, = 0.025dm³

Concentration of HB, $C_B$ = 3.0mol/dm³

volume of HB, $V_B$ = 45.0cm³ = 0.045dm³

To determine the H+ (aq) concentration in mol/dm³ in the resulting solution, we apply concentration formula;

$C_iVi = C_fV_f$

where;

$C_i$ is initial concentration

$V_i$ is initial volume

$C_f$ is final concentration of the solution

$V_f$ is final volume of the solution

$C_iV_i = C_fV_f\\\\Based \ on \ this\ question, we \ can \ apply\ the \ formula\ as;\\\\C_A_iV_A_i + C_B_iV_B_i = C_fV_f\\\\C_A_iV_A_i + C_B_iV_B_i = C_f(V_A_i\ +V_B_i)\\\\6*0.025 \ + 3*0.045 = C_f(0.025 + 0.045)\\\\0.285 = C_f(0.07)\\\\C_f = \frac{0.285}{0.07} = 4.07 = 4.1 \ mol/dm^3$

Therefore, the H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

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2 years ago

A patient is having an allergic reaction and takes a 12.5mg tablet of the over‑the‑counter antihistamine diphenhydramine hydroch

horsena [70]

12.5 mg of the tablet contains 2.58×10¹⁹ molecules of diphenhydramine hydrochloride, C₁₇H₂₂ClNO

From Avogadro's hypothesis,

<h3>1 mole of any substance = 6.02×10²³ molecules </h3>

Therefore,

1 mole of C₁₇H₂₂ClNO = 6.02×10²³ molecules

Next, we shall determine the mass (in mg) of 1 mole of C₁₇H₂₂ClNO. This can be obtained as follow:

1 mole of C₁₇H₂₂ClNO = (17×12) + (22×1) + 35.5 + 14 + 16

= 204 + 22 + 35.5 + 14 + 16

= 291.5 g

Multiply by 1000 to express in mg

291.5 × 1000 = 291500 mg

Thus,

Therefore,

291500 mg of C₁₇H₂₂ClNO = 6.02×10²³ molecules

Finally, we shall determine the number molecules in 12.5 mg of C₁₇H₂₂ClNO. This can be obtained as follow:

291500 mg of C₁₇H₂₂ClNO = 6.02×10²³ molecules

Therefore

12.5 mg of C₁₇H₂₂ClNO = $\frac{12.5 * 6.02*10^{23}}{291500}\\$

<h3>12.5 mg of C₁₇H₂₂ClNO = 2.58×10¹⁹ molecules </h3>

Therefore, we can conclude that 12.5 mg of the tablet contains 2.58×10¹⁹ molecules of diphenhydramine hydrochloride, C₁₇H₂₂ClNO

Learn more: brainly.com/question/24717429

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1 year ago