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NeX [460]
2 years ago
6

For a single component system, why do the allotropes stable at high temperatures have higher enthalpies than allotropes stable a

t low temperatures, e.g. H (γ-Fe) > H (α-Fe)?
Chemistry
1 answer:
solniwko [45]2 years ago
8 0

Answer:

The difference in the magnetic orientation influences the thermal stability of the allotropes of iron.

Explanation:

It is known that the allotropes of iron exist in three phases: α - phase, β- phase, and γ-phase. However, two prominent structures are the  α - phase and γ-phase. Now, let us look at the two phrases:

α - phase

This structure is a body-centered cube. It means that the unit cell structure resembles a cube. The lattice points are in the face of the cube. This subsequently affects the magnetic structure of the iron allotrope.

γ-phase

This allotrope has a lattice structure. It simply means that the structure has lattice points on the face of the cube. The structure generally affects the magnetic properties of the transitional metal; hence the stability of the γ-phase compared to α-phase.

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Butane (c4h10) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. given δh°f[c4h10(g)] = –124.7
vagabundo [1.1K]

The value of Δ H butane (g) = -124.7 kJ/mol

The value of Δ H CO2 (g) = -393.5 kJ/mol

The value of Δ H H2O (g) = -241.8 kJ/mol

Mass of butane, m = 8.30 gm

Molar mass of butane is 58 gm/mol

Consider the reaction,

C₄H₁₀ + 6.5 O₂ = 4CO₂ + 5H₂O

Calculating the value of Δ H° rxn:

ΔH°rxn = ∑nH° f (products) - ∑nH° f (reactants)

Substituting the values we get,

Δ H° rxn = 4 (-393.5) + 5 (-241.8) - (-124.7)

= -1574 -1209 + 124.7

= -2783 - 124.7

= -2658.3 kJ/mol

Now, calculate the number of moles of butane in 8.30 gm.

Number of moles = mass/molar mass

= 8.30 / 58

= 0.143 moles

Thus, the total energy released in the reaction is,

Q = number of moles × ΔH° rxn

= 0.143 × (2658.3)

= 380.14 kJ

Hence, the total heat released in the reaction is 380.14 kJ.

6 0
2 years ago
Select the correct answer.
Phoenix [80]

Answer:

Molecular formula =  C₆H₁₂O₆

Explanation:

Given data:

Mass of hydrogen = 31.7 g

Mass of carbon = 283.4 g

Mass of oxygen = 377.4 g

Molar mass of compound = 176.124 g/mol

Molecular formula = ?

Solution:

Number of gram atoms of H = 31.7 / 1.01 = 31.4

Number of gram atoms of O = 377.4 / 16 = 23.6

Number of gram atoms of C = 283.4 / 12 = 23.6

Atomic ratio:

            C                      :      H                 :         O

           23.6/23.6         :     31.4/23.6     :       23.6/23.6

              1                      :        1.33              :        1

C : H : O =3 (1 : 1.33 : 1 )

Empirical formula is C₃H₄O₃.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 3×12+4+3×16 = 88

n = 176.124 / 88

n = 12

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₃H₄O₃)

Molecular formula =  C₆H₁₂O₆

7 0
2 years ago
If 73.5 mL of 0.200 M KI(aq) was required to precipitate all of the lead(II) ion from an aqueous solution of lead(II) nitrate, h
frutty [35]

Answer:

There were 0.00735 moles Pb^2+ in the solution

Explanation:

Step 1: Data given

Volume of the KI solution = 73.5 mL = 0.0735 L

Molarity of the KI solution = 0.200 M

Step 2: The balanced equation

2KI + Pb2+ → PbI2 + 2K+

Step 3: Calculate moles KI

moles = Molarity * volume

moles KI = 0.200M * 0.0735L = 0.0147 moles KI

Ste p 4: Calculate moles Pb^2+

For 2 moles KI we need 1 mol Pb^2+ to produce 1 mol PbI2 and 2 moles K+

For 0.0147 moles KI we need 0.0147 / 2 = 0.00735 moles Pb^2+

There were 0.00735 moles Pb^2+ in the solution

3 0
2 years ago
Question14 of 20If 5.15 g FeCl3 is dissolved in enough water to make exactly 150.0 mL of solution, what is the molar concentrati
Serhud [2]

Answer: 0.635 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{5.15g}{162.4g/mol}=0.0317moles  

V_s = volume of solution  = 150 ml

Molarity=\frac{0.0317\times 1000}{150ml}=0.2114M

FeCl_3\rightarrow Fe^{3+}+3Cl^-

as 1 mole of FeCl_3 gives 3 moles of Cl^- ions

Thus molarity of Cl^- = 3\times 0.2114=0.635M

Molarity of Cl^- = 0.635 M

8 0
2 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°C _____.
MatroZZZ [7]

Answer:

c

Explanation:

1 calorie = 4.184J/g×°C

This also happens to be the specific heat capacity of water, which is the amount of energy it takes to raise the temperature of 1mL of water by 1°C

6 0
2 years ago
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