Answer:
Molar concentration of the weak acid solution is 0.0932
Explanation:
Using the formula:
Where Ca = molarity of acid
Cb = molarity of base = 0.0981 M
Va = volume of acid = 25.0 mL
Vb = volume of base = 23.74 mL
na = mole of acid
nb = mole of base
Since the acid is monopromatic, 1 mole of the acid will require 1 mole of NaOH. Hence, na = nb = 1
Therefore,
Ca = 0.0981 x 23.74/25.0
= 0.093155 M
To 4 significant figure = 0.0932 M
<u>Answer:</u> The chemical equations and equilibrium constant expression for each ionization steps is written below.
<u>Explanation:</u>
The chemical formula of carbonic acid is . It is a diprotic weak acid which means that it will release two hydrogen ions when dissolved in water
The chemical equation for the first dissociation of carbonic acid follows:
The expression of first equilibrium constant equation follows:
The chemical equation for the second dissociation of carbonic acid follows:
The expression of second equilibrium constant equation follows:
Hence, the chemical equations and equilibrium constant expression for each ionization steps is written above.