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2 years ago

Consider the elements in Group 14. Which element has the highest electron affinity? A) Carbon B) Germanium C) Lead D) Silicon

1 answer:

3 0

Electron affinity is a measure of the tendency of a neutral atom to gain electrons and form a negative ion. It can be represented by a general equation:

X + e- → X-

The value of electron affinity decreases on moving down a group. This is because on moving down a group the atomic size increases as a result the added electron feels less pull or attraction towards the nucleus.

In group 14, Carbon 'C' is the first member and therefore will have the highest electron affinity.

Ans : A) Carbon

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a 280.0 mL sample of neon exerts a pressure of 660.0 toff at 26.0 celsius. at what temperture would it exert a pressure of 940.0

bixtya [17]

Answer:

T₂ = 669.2 K

Explanation:

Given data:

Initial pressure = 660 torr

Initial temperature = 26 °C (26 +273 = 299 K)

Final volume = 280 mL ( 280/1000 = 0.28 L)

Final pressure = 940.0 torr

Final volume = 0.44 L

Final temperature = ?

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂ T₁ /P₁V₁

T₂ = 940 torr × 0.44 L × 299 K / 660 torr × 0.28 L

T₂ = 123666. 4 torr. L. K / 184.8 torr. L

T₂ = 669.2 K

3 0

1 year ago

Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange

SIZIF [17.4K]

Answer:

A. 10.0 grams of ethyl butyrate would be synthesized.

B. 57.5% was the percent yield.

C. 7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

Explanation:

$CH_3CH_2CH_2CO_2H(l)+CH_2CH_3OH(l)+H^+\rightarrow CH_3CH_2CH_2CO_2CH_2CH_3(l)+H_2O(l)$

Moles of butanoic acid = $\frac{7.60 g}{88 g/mol}=0.08636 mol$

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

$\frac{1}{1}\times 0.08636 mol=0.08636 mol$ of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 100%

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$100\%=\frac{\text{Experimental yield}}{10.0 g}\times 100$

Experimental yield = 10.0 g

10.0 grams of ethyl butyrate would be synthesized.

Theoretical yield of ethyl butyrate = 10.0 g

Experimental yield ethyl butyrate = 5.75 g

Percentage yield of the reaction = ?

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$=\frac{5.75 g}{10.0 g}\times 100=57.5\%$

57.5% was the percent yield.

Moles of butanoic acid = $\frac{7.60 g}{88 g/mol}=0.08636 mol$

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

$\frac{1}{1}\times 0.08636 mol=0.08636 mol$ of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 78.0%

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$78.0\%=\frac{\text{Experimental yield}}{10.0 g}\times 100$

Experimental yield = 7.80 g

7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

8 0

1 year ago

If excess caso4(s) is mixed with water at 25 ∘c to produce a saturated solution of caso4, what is the equilibrium concentration

Ray Of Light [21]

Answer:

The equlibrium concentration sof Ca+2 ion willl be 4.9×10∧-3 M

Data Given:

Ksp of CaSO4 = 2.4 × 10∧-5

CaSO4 ⇔ Ca+2 + SO4∧-2

Solution:

Ksp = [Ca+2].[ SO4∧-2]

2.4 × 10∧-5 = [x].[x]= x²

x = 4.9×10∧-3 M

Result:

The conc. of Ca+2 ion is 4.9×10∧-3 M

3 0

1 year ago

Titanium dioxide, TiO₂, reacts with carbon and chlorine to give gaseous TiCl₄: TiO₂+2C+2CI₂−TiCI₄+2CO The reaction of 7.39 kg ti

Dima020 [189]

Answer:

17.57kg of $TiCl_{4}$ and its percentage yield is 81.0%

Explanation:

Through the reaction you can get the theoretical amount of $TiCl_{4}$ that must be produced.

$7.39kgTiO_{2}x\frac{1kmolTiO_{2} }{79.867kgTiO_{2}}x \frac{1kmolTiCl_{4}}{1kmolTiO_{2}}x\frac{189.867kgTiCl_{4} }{1kmolTiCl_{4}}=17.57kgTiCl_{4}$

If the amount obtained is less than the theoretical amount, it means that the initial sample was not 100% pure. Now the actual amount obtained is compared with the theoretical amount using a percentage

$yield=\frac{actual amount}{theoretical amount}x100= \frac{14.24kg}{17.57kg}x100$ =81.0%

3 0

2 years ago

The molecular mass of methyl ethanoate is 74.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoa

kobusy [5.1K]

Isomers are the compounds having same molecular formula but different structural formula.

Since, molecular formula is isomers are same, they have same mass.

Now, methyl ethanoate is an isomer of propanoic acid, hence they have same mass.

∴ Molecular mass of propanoic acid = 74.1 amu or 74.1 g/mol

4 0

2 years ago