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2 years ago

Assume that 8.5 L of iodine gas are produced at STP according to the following balanced equation:

2 answers:

3 0

Balanced chemical equation is as;

 2 Kl + Cl₂ → 2 KCl + I₂

1) Moles of I₂ produced;

22.4 L volume is occupied by = 1 mole of I₂ at STP
So,
8.5 L of I₂ will be occupied by = X mole of I₂ at STP

Solving for X,
X = (8.5 L × 1 mol) ÷ 22.4 L

X = 0.379 Moles of I₂

2) Moles of Cl₂ used;

22.4 L I₂ utilized = 1 mole of Cl₂ gas
So,
8.5 L of I₂ will utilize = X mole of Cl₂ gas

Solving for X,
X = (8.5 L × 1 mol) ÷ 22.4 L

X = 0.379 Moles of Cl₂

3) Grams of Cl₂ used;

As,
Moles = Mass / M.mass
Or,
Mass = Moles × M.mass

Mass = 0.379 mol × 70.90 g.mol⁻¹

Mass = 26.87 grams of Cl₂

Nat2105 [25]2 years ago

3 0

Answer:

0.38
0.38
27

Explanation:

right on edge

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Stephanie has been doing research on how petroleum is formed. She says that oxygen must be present while the tiny plants and ani

madreJ [45]

Answer:

No, Stephanie is incorrect. Formation of petroleum cannot take place under the presence of oxygen.

Explanation:

Since, the petroleum is fossil product. Fossil fuel are formed under high pressure and temperature with absence of oxygen for longer period. so the way she is performing is completely incorrect. With the presence of oxygen in no way petroleum will be formed. The temperature and pressure should be in different combination for the formation of the petroleum. Along with the layers of sediments to maintain the pressure is required.

5 0

2 years ago

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A mass of 5.4 grams of aluminum (al) reacts with an excess of copper (ii) chloride (cucl2) in solution, as shown below. 3cucl2 2

horrorfan [7]

Answer:

Mass of copper produced is 19.07g

Explanation:

Let's bring out the chemical equation;

3CuCl2 + 2Al → 2AlCl3 + 3Cu

3 : 2 : 2 : 3

Upon confirming that the reaction is indeed balanced, we can proceed.

The questions asks to calculate mass of Cu formed when a mass of 5.4g of Al is being used.

From the equation, what is the relationship between Al and Cu?

2 mol of Al would react to form 3 mol of Cu

Expressing this in terms of mass, we have;

mass = no. of moles * molar mass

Mass of Aluminium = 2 * 26.98 = 53.98 g

Mass of Copper = 3 * 63.546 = 190.638g

This means;

53.98 g of Al would react to form 190.638g of Cu

So how much Cu would form from 5.4 g of Al?

This leads us to;

53.98 = 190.638

5.4 = x

Upon cross multiplication, we are left with;

x = (190.638 * 5.4) / 53.98

x = 19.07 g

Mass of copper produced is 19.07g

8 0

2 years ago

At 800 K, the equilibrium constant, Kp, for the following reaction is 3.2 × 10–7. 2 H2S(g) ⇌ 2 H2(g) + S2(g) A reaction vessel a

djverab [1.8K]

Answer:

0.008945 atm

Explanation:

In the reaction:

2H2S(g) ⇌ 2 H2(g) + S2(g)

Kp is defined as:

$Kp = P_{H_{2}}^2P_{S_{2}} / P_{H_{2}S}^2$

Where P is the pressure of each compound in equilibrium.

If initial pressure of H2S is 3.00atm, concentrations in equilibrium are:

H2S = 3.00 atm - 2X

H2 = 2X

S2: = X

Replacing:

$3.2x10^{-7} = (2X)^2X / (3-2X)^2$

$3.2x10^{-7} = 4X^3 / 9- 6X+4X^2$

0 = 4X³ - 1.28x10⁻⁶X² + 1.92x10⁻⁶X - 2.88x10⁻⁶

Solving for X:

X = 0.008945 atm

As in equilibrium, pressure of S2 is X, pressure is 0.008945 atm

7 0

2 years ago

There are three puddles of different sizes on a sidewalk:

nalin [4]

The one property that you can always depend on to change vapor pressure is temperature. So as the water's temperature increases so does the vapor pressure. The warmer the water, the higher the vapor pressure.

Blank one: Hot water

Blank Two: Temperature

7 0

2 years ago

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The decomposition of nitramide, O2NNH2, in water has the chemical equation and rate law O2NNH2(aq)⟶N2O(g)+H2O(l)rate=k[O2NNH2][H

FinnZ [79.3K]

Answer:

It can be concluded that the third step of the reaction is very fast, in this way, it does not contribute to the rate law

Explanation:

Please, observe the solution in the attached Word document.

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