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Galina-37 [17]
1 year ago
14

If K3PO4= 0.250M, how many grams of K3PO4 are in 750.0ml of solution? Remember that M is the same as mol/L. Answer: 39.8g

Chemistry
1 answer:
sweet-ann [11.9K]1 year ago
4 0

Answer:

See below

Explanation:

Molarity = moles/Volume in Liters = (grams/formula wt)/Vol in Liters

=> Grams of solute = Molarity x Vol in Liters x formula wt

= (0.250M)(0.750L)(212.3g/mol)

= 39.8 grams

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A 52.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 26.0 mL of KOH at 25 ∘C.
prohojiy [21]
The balanced equation for the above reaction is 
HBr + KOH ---> KBr + H₂O
stoichiometry of HBr to KOH is 1:1
HBr is a strong acid and KOH is a strong base and they both completely dissociate.
The number of HBr moles present - 0.25 M / 1000 mL/L x 52.0 mL = 0.013 mol
The number of KOH moles added - 0.50 M / 1000 mL/L x 26.0 mL  = 0.013 mol
the number of H⁺ ions = number of OH⁻ ions
therefore complete neutralisation occurs. 
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7 0
2 years ago
Which element can form a chloride with a general formula of MCl2 or MCl3
zhannawk [14.2K]
Oxidation state number can be used to determine the unknown element in these two compounds. They are used to determine how many electrons are given, taken or shared to form compounds.

Recall the elementary rules of oxidation numbers.

1. The sum of all oxidation numbers in a neutral compound is zero.
2. Chlorine, bromine, iodine have oxidation number of -1 ( except compounds with fluorine and oxygen)

Let oxidation number of element M be x.
Check rule 2. Chlorine has -1 oxidation number.

Now we write an equation of MCl₂ (neutral compound)
x + (2 * -1)= 0 ⇒ x₁= +2

For MCl₃
x + (3 * -1)=  0 ⇒ x₂= +3

So element has 2 different oxidation number in compounds, +2 and +3.

The element is iron (Fe) since it has +2 and +3  oxidation numbers in the compounds.

You need to learn it by hard. Unfortunately there is not an easier way to work out with these oxidation numbers.

The answer is iron (Fe).

5 0
1 year ago
Write the equations that represent the first and second ionization steps for hydroselenic acid (H2Se) in water. (Use H3O+ instea
Otrada [13]

Answer:

The equations are

1) H_{2}Se+H_{2}O--> H_{3}O^{+}+HSe^{-}

2) HSe^{-} +H_{2}O--> H_{3}O^{+}+Se^{-2}

Explanation:

There are two ionization steps in the dissociation of hydroselenic acid.

In first dissociation the H₂Se loses one proton and forms hydrogen selenide ion as shown below:

H_{2}Se+H_{2}O--> H_{3}O^{+}+HSe^{-}

The next step is again removal of a proton from the base formed above.

HSe^{-} +H_{2}O--> H_{3}O^{+}+Se^{-2}

4 0
2 years ago
Jeff has 10 grams of water and 10 grams of vegetable oil in separate containers. Both liquids have a temperature of 24°C. Jeff h
Anna11 [10]
I think the answer would be that vegetable oil is a better conductor of heat than water.
8 0
2 years ago
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Of elements N, O, Cl, Na, and Which two would likely have similar chemical properties and why
ch4aika [34]
Oxygen and Nitrogen would be the most similar of the elements listed, because they are the closest in the periodic table. This isn't a very good reason for anything, but the two do have some similar properties. They are both non-metals, they are both highly electronegative, they are both diatmoic gasses in their natural states, they have a similar number of valence electrons, they are both generally oxidizing agents. Oxygen and Chlorine are also quite similar, but not quite as similar as Oxygen and Nitrogen.
5 0
2 years ago
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