If K3PO4= 0.250M, how many grams of K3PO4 are in 750.0ml of solution? Remember that M is the same as mol/L. Answer: 39.8g
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Explanation:
The reaction equation will be as follows.
Hence, moles of Na = moles of electron used
Therefore, calculate the number of moles of sodium as follows.
No. of moles =
= (as 1 kg = 1000 g)
= 195.65 mol
As, Q = where F = Faraday's constant
=
= mol C
Relation between electrical energy and Q is as follows.
E =
Hence, putting the given values into the above formula and then calculate the value of electricity as follows.
E =
=
=
As 1 J = kWh
Hence, kWh
= 3.39 kWh
Thus, we can conclude that 3.39 kilowatt-hours of electricity is required in the given situation.
Answer:
Empirical formula: CH2
Molecular formula: C5H10
