Answer:
The empirical formula of compound is C₂H₆O.
Explanation:
Given data:
Mass of carbon = 12 g
Mass of hydrogen = 3 g
Mass of oxygen = 8 g
Empirical formula of compound = ?
Solution:
First of all we will calculate the gram atom of each elements.
no of gram atom of carbon = 12 g / 12 g/mol = 1 g atoms
no of gram atom of hydrogen = 3 g / 1 g/mol = 3 g atoms
no of gram atom of oxygen = 8 g / 16 g/mol = 0.5 g atoms
Now we will calculate the atomic ratio by dividing the gram atoms with the 0.5 because it is the smallest number among these three.
C:H:O = 1/0.5 : 3/0.5 : 0.5/0.5
C:H:O = 2 : 6 : 1
The empirical formula of compound will be C₂H₆O
Answer:
Newton's Third Law
Explanation:
Newton's Third Law stipulates that for every action there is an equal and opposite reaction.
So when the two players are tackling they exert a force on each other.
If player 1 tackles (exerts a force) player 2, player 2 will exert an equal and opposite reaction on player 1 as stated in Newton's Third Law.
Therefore when they tackle each other so hard they both experience reaction forces so powerful that they fly in opposite directions.
Thus this is an example of the Newton's Third Law.
Answer:
The concentration is 0,2925M
Explanation:
We use the formula
C initial x V initial = C final x V final
11,7 M x 25 ml = C final x 1000 ml
C final= (11,7 M x 25 ml)/1000 ml = 0, 2925 M
(This formula applies to liquid solutions)
<u>Answer:</u> The chemical equations and equilibrium constant expression for each ionization steps is written below.
<u>Explanation:</u>
The chemical formula of carbonic acid is
. It is a diprotic weak acid which means that it will release two hydrogen ions when dissolved in water
The chemical equation for the first dissociation of carbonic acid follows:

The expression of first equilibrium constant equation follows:
![Ka_1=\frac{[H^+][HCO_3^{-}]}{[H_2CO_3]}](https://tex.z-dn.net/?f=Ka_1%3D%5Cfrac%7B%5BH%5E%2B%5D%5BHCO_3%5E%7B-%7D%5D%7D%7B%5BH_2CO_3%5D%7D)
The chemical equation for the second dissociation of carbonic acid follows:

The expression of second equilibrium constant equation follows:
![Ka_2=\frac{[H^+][CO_3^{2-}]}{[HCO_3^-]}](https://tex.z-dn.net/?f=Ka_2%3D%5Cfrac%7B%5BH%5E%2B%5D%5BCO_3%5E%7B2-%7D%5D%7D%7B%5BHCO_3%5E-%5D%7D)
Hence, the chemical equations and equilibrium constant expression for each ionization steps is written above.
Answer:
Mass of CuSO4.H2O obtained: 
Explanation:
The molecular weight of the salt is: 
<u>In the solution</u>: 12.5 g of CuSO4
In moles: 
<u>Mass of wate</u>r:
5 moles of water per mol of salt: 
Mass of CuSO4.H2O obtained: 