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Irina18 [472]
1 year ago
13

Using the data, which of the following is the rate constant for the rearrangement of methyl isonitrile at 320 ∘C? (HINT: the act

ivation energy for this reaction is 160 kJ/mol) T(K) 1/T(K−1) ln k 462.9 2.160×10−3 -10.589 472.1 2.118×10−3 -9.855 503.5 1.986×10−3 -7.370 524.4 1.907×10−3 -5.757 Using the data, which of the following is the rate constant for the rearrangement of methyl isonitrile at 320 ? (HINT: the activation energy for this reaction is 160 ) ln 462.9 -10.589 472.1 -9.855 503.5 -7.370 524.4 -5.757 8.1×10−15 s−1 2.2×10−13 s−1 2.7×10−9 s−1 2.0×10−1 s−1 9.2×103 s−1

Chemistry
1 answer:
svp [43]1 year ago
3 0

Explanation:

Below is an attachment containing the solution.

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An aluminum ion has a charge of +3, and an oxide has a charge of -2. What would be the product of a reaction between these two e
kozerog [31]

The product of a reaction between these two elements is Al_{2} O_{3}.

Explanation:

The oxidation state of an ion in a compound is equal to its charge.

The aluminum having a charge of +3 because oxidation state is +3

The oxide is having charge of -2

The product of these reactants will produce a chemical compound.

The compound formed is Al_{2} O_{3}  i.e Aluminium oxide. The compound while getting formed will share the charge and cation A+ will have the charge of anion and anion will have the charge of cation. This will result in a compound as there should be a neutral charge on the compound formed.

The <em>+</em><em>3 charge of the cation Al+ will go to anion oxide O2- and the charge of anion -2 will go with cation Al+. </em>

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2 years ago
A wave hits a wall as shown. A brick wall with a green arrow pointing to the wall from below and right at a shallow angle. Anoth
Dominik [7]

Answer:

A wave reflection interaction (reflected by the wall)

Explanation:

In a reflection, the propagating wave is bounced off the reflecting surface because the medium of the surface prevents the propagation of the wave through it, such that wave is redirected at an angle equal to the angle of incident on the reflecting surface

Reflection takes place with the different forms of waves, such as sound wave, water waves, and light wave

The objects around us are seen with the aid of reflection of light from a light source such that the reflected light enters our eyes after being reflected on the surface of the object, and the object is seen.

3 0
2 years ago
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What is an azeotrope? 2. Under what conditions is it better to perform a steam distillation (instead of, say, a simple distillat
aleksandrvk [35]

Answer:

Explanation:

1.)azeotrope is a mixture of two or more liquid components under constant boiling, it has a constant mole fraction composition of present component which can be homogeneous or heterogeneous.

2.)the condition which it's best performed when there's liquids that is non-volatile which boils higher than other liquids with at least 26 degrees .

steam azentropic distillation

3.During a steam distillation, How to know if the organic compound is still coming over is when you see the solution becoming cloudy or when there is existence of two layers.

4.)The end of the steam distillation, the receiving flask should contain two layers of liquid, and the chemical identity of these two liquids most contain

A.) Layers that are mostly water H2O

B.) Layers that are mostly products

5.)What is the purpose of adding 10% sodium carbonate solution to the distillate if it is acidic to litmus is to neutralize the distillate.

7 0
2 years ago
A 1.850 g mixture of SrCO3 and SrO is heated. The SrCO3 decomposes to SrO and CO2. What was the mass percentage of SrCO3 in the
Oliga [24]
<span>decomposition of SrCO3 to SrO and CO2 =change in mass

 moles of CO2 =(1.850 g - 1.445 g). 
</span>Mass of <span>C<span>O2</span></span><span> in mixture: 1.850-1.445 = 0.405g
</span>0.405g/44.01 g/mol <span>C<span>O2</span></span><span> = 0.0092 moles </span><span>C<span>O2</span></span><span>.
</span>ratio of <span>C<span>O2</span></span><span> to SrO in Sr</span><span>C<span>O3</span></span><span> is 1:1
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or 73.41% Sr<span>C<span>O3</span></span><span>.
</span>hope this helps
5 0
2 years ago
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In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat
LiRa [457]

Answer: 1.14

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M

To calculate pH of gastric juice:

molarity of H^+ = 0.072

pH=-log[H^+]

pH=-log(0.072)=1.14

Thus the pH of the gastric juice is 1.14

3 0
2 years ago
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