<span>336*280 i believe... i hope this helps
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<span>If a mole of aluminum weighs 26.98 grams, that means 1 atom of aluminum weighs = (26.98 g/mole) / (6.023 x 10^23 atoms/mole) = 4.479 x 10^-23 grams,
</span>so, it is not possible because 1 atom weighs that much we calculated which is <span>almost 100 times more than the amount you mentioned</span>
<span>Answer:
M in this equation is molar mass. If A is He and B is O2 then MA = 4 g/mol and MB = 32 g/mol
rate A = 1.5L/24hr rate B = 1.5L/?hr and rateA/rateB = ?/24</span>
Example of an element that has an electron distribution ending in s2p1 is Na or sodium. The complete electron configuration of Na 1s22s22p63s<span>1. </span>Example of an element that has an electron distribution ending in s2d2 is Ca or calcium. The complete electron configuration of Ca is 1s22s22p63s23p64s2.
Please see the attached photo for the answer. Basically, you break the double bond between the Carbons and add Hydrogens to the carbons to fulfill the octet.
Shout out to my co-worker who helped me solve the problem!
