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Talja [164]
2 years ago
14

Which of the following statements concerning the attraction of ions to polar molecules is/are CORRECT? 1. The force of attractio

n between an ion and a polar molecule is inversely proportional to the square of the distance between the center of the ion and the oppositely charged pole of the dipole. 2. The higher the ion charge, the stronger the attraction between the ion and a polar molecule. 3. The greater the magnitude of the dipole, the greater the attraction between the ion and a polar molecule.
Chemistry
1 answer:
Kitty [74]2 years ago
6 0

Answer:

1, 2 and 3 are correct.

Explanation:

The force of the attraction is calculated by Coulomb's law as:

\frac {K\times q_1\times q_2}{d^2}

Where,  

K is the Coulomb's constant having value 9×10⁹ N. m²/C²

q_1\ and\ q_2 are the charges on the dipole and ion respectively.

d is the distance between them.

Since F is inversely proportional to square of distance between them, so statement 1 is true.

F is directly proportional to the charge , so on increasing charge, force of attraction increases. Hence, statement 2 is true.

The greater the magnitude of the dipole means the greater the charge on dipole. Hence, statement 3 is also true.

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At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?
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The temperature that  would  the volume of a gas  be 0.550l  if  it  had a volume of 0.432 L  at  -20.0  c is calculated  using the Charles law formula

that is   v1/T1=V2/T2
V1=0.550 l
t1=?
T2= -20 c +273 = 253 K
v2= 0.432 l

by  making T1  the subject of the formula  T1= V1T2/V2


T1=  (0.55lL x253)/  0.432 l = 322.11 K  or  322.11-273 = 49.11 C
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2 years ago
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Are the strengths of the interactions between the particles in the solute and between the particles in the solvent before the so
Colt1911 [192]

Answer:

Less than

Explanation:

The process of dissolution occurs as a kind of "tug of war". On one side are the solute-solute and solvent-solvent interaction forces, while on the other side are the solute-solvent forces.

Only when the solute-solvent forces are strong enough to overcome the pre-mixing forces do they overcome the "tug of war", and thus dissolution occurs.

Thus, it is concluded that the interaction forces between solute particles and solvent particles before they are combined are less than the interaction forces after dissolution.

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SnO2 is reduced by carbon according to this reaction: SnO2 + C ???? Sn + CO2. How many liters of CO2 are produced if 300.0 grams
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Explanation:

The given reaction is as follows.

         SnO_{2} + C \rightarrow Sn + O_{2}

a).   Molar mass of SnO_{2} is [(mass of Sn) + (2 × mass of O)].

Therefore, molar mass of SnO_{2} = (118.7 + 2 × 16) g/mol = 150.7 g/mol

Since, it is known that number of moles equal mass divided by molar mass. So, moles of Sn will be calculated as follows.

               No. of moles = \frac{mass}{molar mass of SnO_{2}}

                                      = \frac{300 g}{150.7 g/mol}

                                      = 2.53 mol

As it is given that 1 mole of SnO_{2} produces 1 moles of Sn and 1 moles of CO_{2}. Hence, 2.53 moles of SnO_{2} will also produce 2.53 moles of Sn and 2.53 moles of CO_{2}.

Volume of 1 mole of CO_{2} at STP is 22.4 L. Therefore, volume of 2.53 moles of CO_{2} will be calculated as follows.

                  2.53 × 22.5 L = 56.67 L

Hence, 56.67 L of CO_{2} are produced if 300.0 grams of tin are produced at STP.

b).  Mass of tin is given as 1800.0 g. So, number of moles will be calculated as follows.

               No. of moles = \frac{mass}{molar mass of tin}

                                      = \frac{1800.0 g}{118.7 g/mol}

                                      = 15.2 moles

As 15.2 moles of SnO_{2} produces 15.2 moles of Sn. Therefore, weight of SnO_{2} will be calculated as follows.

                   Mass = no. of moles × molar mass of SnO_{2}

                             = 15.2 moles × 150.7 g/mol

                             = 2290.64 g

Hence, 2290.64 grams of SnO_{2} are required to produce 1800.0 grams of tin.

c).   Mass of carbon given is 100.0 grams.

             No. of moles = \frac{mass}{molar mass of carbon}

                                    = \frac{100 g}{12 g/mol}

                                      = 8.33 moles

As, 1 mole of carbon is produced by 1 mole of tin. So, 8.33 mole of carbon will be produced by 8.33 moles of tin.

Therefore, calculate mass of tin produced as follows.

                        Mass = no. of moles × molar mass of Sn

                             = 8.33 moles × 118.7 g/mol

                             = 988.8 g

Hence, 988.8 grams of tin will be produced per 100 grams of carbon used.

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Answer:

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