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USPshnik [31]
2 years ago
15

A meal containing a burger, fries, and a milkshake contains 53.0 grams of fat, 38.0 grams of protein, and 152 grams of carbohydr

ate. The respective fuel values for protein, fat, and carbohydrate are 17, 38, and 17 kJ/g, respectively. If swimming typically burns 1100.0 kJ/hour, ________ minutes of swimming are required to completely burn off the meal.
Chemistry
1 answer:
ollegr [7]2 years ago
5 0

Answer:

4.8 h

Explanation:

The meal contains 53.0 grams of fat. If fat provides 38 kJ/g, the energy supplied is:

53.0 g × 38 kJ/g = 2.0 × 10³ kJ

The meal contains 38.0 grams of protein. If protein provides 17 kJ/g, the energy supplied is:

38.0 g × 17 kJ/g = 6.5 × 10² kJ

The meal contains 152 grams of carbohydrate. If carbohydrate provides 17 kJ/g, the energy supplied is:

152 g × 17 kJ/g = 2.6 × 10³ kJ

The total energy supplied is:

2.0 × 10³ kJ + 6.5 × 10² kJ + 2.6 × 10³ kJ = 5.3 × 10³ kJ

Swimming burns 1100.0 kJ/hour. The time required to burn 5.3 × 10³ kJ is:

5.3 × 10³ kJ × (1 h/1100.0 kJ) = 4.8 h

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A sample of sodium reacts completely with 0.355 kg of chlorine, forming 585 g of sodium chloride. What mass of sodium reacted?
Kay [80]

Answer:

The mass of sodium that reacted is 230 grams

Explanation:

The balance equation of the reaction is first written .

sodium = Na

Chlorine = Cl2

sodium chloride = NaCl

2Na + Cl2 → 2NaCl

from the balance equation we calculate the molar mass involve in the reaction

Molar mass of sodium from the equation = 23(2) = 46 g

molar mass of sodium chloride from the eqaution = 23 × 2 + 35.5 × 2 = 46 + 71 = 117 g

If 46g of sodium is in 117 g of sodium chloride

? gram will be in 585 g of sodium chloride

cross multiply

46 × 585/117 = 26910/117  = 230 g

The mass of sodium that reacted is 230 grams

5 0
2 years ago
Elements that’s are gases, brittle & poor conductors at room temperature are
vlabodo [156]

I think the answer is C for this question

5 0
2 years ago
1) How many aluminum atoms are there in 3.50 grams of Al2O3?
drek231 [11]

Answer:

Aluminium atoms =  4.13 *10^22 aluminium atoms

The correct answer is E

Explanation:

Step 1: Data given

Mass of Al2O3 = 3.50 grams

Molar mass of Al2O3 = 101.96 g/mol

Number of Avogadro = 6.022 * 10^23 /mol

Step 2: Calculate moles Al2O3

Moles Al2O3 = mass Al2O3 / molar mass Al2O3

Moles Al2O3 = 3.50 grams / 101.96 g/mol

Moles Al2O3 = 0.0343 moles

Step 3: Calculate moles Aluminium

In 1 mol Al2O3 we have 2 moles Al

in 0.0343 moles Al2O3 we have 2*0.0343 = 0.0686 moles Al

Step 4: Calculate aluminium atoms

Aluminium atoms =  moles aluminium * Number of Avogadro

Aluminium atoms =  0.0686 * 6.022 * 10^23

Aluminium atoms =  4.13 *10^22 aluminium atoms

The correct answer is E

3 0
2 years ago
Sodium thiosulfate (Na2S2O3), photographer’s
vova2212 [387]

3Na2S2O3 + AgBr ------>Na5[Ag(S2O3) 3] +NaBr

from equation 3 mol 1 mol

given x mol 0.10 mol


x= (3*0.10)/1=0.30 mol Na2S2O3


Answer: 0.30 mol Na2S2O3

3 0
2 years ago
Read 2 more answers
A 103.8g sample of nitric acid solution that is 70.0% HNO3 contains by mass
soldi70 [24.7K]
w/w percentage <span>
               = mass of the pure compound / total mass of the sample x 100%

70% HNO₃ contains by mass means every 100 g of sample has 70 g of HNO₃.</span><span>

The mass of solution = 103.8 g
Hence the mass of HNO₃ = 103.8 g x 70%</span><span>
                                         = 103.8 g x (70 / 100)
<span>                                         = 72.66 g = 72.7 g.</span></span>
3 0
2 years ago
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