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USPshnik [31]
2 years ago
15

A meal containing a burger, fries, and a milkshake contains 53.0 grams of fat, 38.0 grams of protein, and 152 grams of carbohydr

ate. The respective fuel values for protein, fat, and carbohydrate are 17, 38, and 17 kJ/g, respectively. If swimming typically burns 1100.0 kJ/hour, ________ minutes of swimming are required to completely burn off the meal.
Chemistry
1 answer:
ollegr [7]2 years ago
5 0

Answer:

4.8 h

Explanation:

The meal contains 53.0 grams of fat. If fat provides 38 kJ/g, the energy supplied is:

53.0 g × 38 kJ/g = 2.0 × 10³ kJ

The meal contains 38.0 grams of protein. If protein provides 17 kJ/g, the energy supplied is:

38.0 g × 17 kJ/g = 6.5 × 10² kJ

The meal contains 152 grams of carbohydrate. If carbohydrate provides 17 kJ/g, the energy supplied is:

152 g × 17 kJ/g = 2.6 × 10³ kJ

The total energy supplied is:

2.0 × 10³ kJ + 6.5 × 10² kJ + 2.6 × 10³ kJ = 5.3 × 10³ kJ

Swimming burns 1100.0 kJ/hour. The time required to burn 5.3 × 10³ kJ is:

5.3 × 10³ kJ × (1 h/1100.0 kJ) = 4.8 h

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<span>A 50-gram sample with a half-life of 12 days will have a remaining mass of 25 grams after its 12-day half-life. Every cycle of a half-life, the sample will lose half of its mass, so if the half-life, itself, is 12 days and the time period passing is 12 days, one half-life has passed and the material will be halved.</span>
8 0
2 years ago
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93.2 mL of a 2.03 M potassium fluoride (KF) solution
Marrrta [24]

Answer:

1.98 M

Explanation:

Given data

  • Initial volume (V₁): 93.2 mL
  • Initial concentration (C₁): 2.03 M
  • Volume of water added: 3.92 L

Step 1: Convert V₁ to liters

We will use the relationship 1 L = 1000 mL.

93.2mL \times \frac{1L}{1000mL} = 0.0932 L

Step 2: Calculate the final volume (V₂)

The final volume is the sum of the initial volume and the volume of water.

V_2 = 0.0932L + 3.92 L = 4.01L

Step 3: Calculate the final concentration (C₂)

We will use the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{2.03 M \times 3.92L}{4.01L} = 1.98 M

3 0
2 years ago
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How many grams of sulfur must be burned to give 100.0 g of So2
andriy [413]

Answer:

50 g of S are needed

Explanation:

To star this, we begin from the reaction:

S(s) + O₂ (g) →  SO₂ (g)

If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.

According to stoichiometry, we can determine the moles of sulfur dioxide produced.

100 g. 1mol / 64.06g = 1.56 moles

This 1.56 moles were orginated by the same amount of S, according to stoichiometry.

Let's convert the moles to mass

1.56 mol . 32.06g / mol = 50 g

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2 years ago
Draw the structure of (z)-3-methylhept-3-ene. be sure the stereochemistry is drawn clearly.
aivan3 [116]
In  alkene  if two  substituent and  hydrogen  are  attached  in  the isomer  may  be cis  or trans. When  two  or  more substitution  are attached  to  an alkene  the  isomer  may  be  Z or E.All cis  are  Z isomer. The  structure  of  (Z)-3-methy-3-heptene  is  as  the  following  attachment

6 0
2 years ago
The bond dissociation energy to break 4 bond(s) in 1 mole of CH₄ molecules is:_____ **Any help would be greatly appreciated!**
frozen [14]

Answer:

The bond dissociation energy to break 4 bonds in 1 mol of CH is 1644 kJ

Explanation:

Since there are 4 C-H bonds in CH₄, the bond dissociation energy of 1 mol of CH₄ is 4 × bond dissociation energy of one C-H bond.

From the table one mole is C-H bond requires 411 kJ, that is 411 kJ/mol. Therefore, 4 C-H bonds would require 4 × 411 kJ = 1644 kJ

So, the bond dissociation energy to break 4 bonds in 1 mol of CH₄ is 1644 kJ

5 0
2 years ago
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