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USPshnik [31]
2 years ago
15

A meal containing a burger, fries, and a milkshake contains 53.0 grams of fat, 38.0 grams of protein, and 152 grams of carbohydr

ate. The respective fuel values for protein, fat, and carbohydrate are 17, 38, and 17 kJ/g, respectively. If swimming typically burns 1100.0 kJ/hour, ________ minutes of swimming are required to completely burn off the meal.
Chemistry
1 answer:
ollegr [7]2 years ago
5 0

Answer:

4.8 h

Explanation:

The meal contains 53.0 grams of fat. If fat provides 38 kJ/g, the energy supplied is:

53.0 g × 38 kJ/g = 2.0 × 10³ kJ

The meal contains 38.0 grams of protein. If protein provides 17 kJ/g, the energy supplied is:

38.0 g × 17 kJ/g = 6.5 × 10² kJ

The meal contains 152 grams of carbohydrate. If carbohydrate provides 17 kJ/g, the energy supplied is:

152 g × 17 kJ/g = 2.6 × 10³ kJ

The total energy supplied is:

2.0 × 10³ kJ + 6.5 × 10² kJ + 2.6 × 10³ kJ = 5.3 × 10³ kJ

Swimming burns 1100.0 kJ/hour. The time required to burn 5.3 × 10³ kJ is:

5.3 × 10³ kJ × (1 h/1100.0 kJ) = 4.8 h

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Mnenie [13.5K]

Answer:

= 230 ppb

Explanation:

Considering that;

1ppm = 1mg/L  

Then;

0.00023g = 0.23mg  

Therefore;

0.00023 g/L = 0.23 mg/L

0.23 mg/L = 0.23 ppm

1 ppm = 100 ppb

Therefore;

0.23 ppm = 0.23 ×1000

                = 230 ppb

5 0
1 year ago
Read 2 more answers
30. how many grams of boric acid, b(oh)3 (fm 61.83), should be used to make 2.00 l of 0.050 0 m solution? what kind of fl ask is
grigory [225]

Answer:

             Mass  =  6.183 g

Solution:

Step 1: Calculate number of moles of Boric acid using following formula,

                                        Molarity  =  Moles ÷ Volume

Solving for Moles,

                                        Moles  =  Molarity × Volume

Putting Values,

                                        Moles  =  0.05 mol.L⁻¹ × 2.0 L

                                        Moles  =  0.1 mol

Step 2: Calculate Mass of Boric Acid using following formula,

                                        Moles  =  Mass ÷ M.mass

Solving for Mass,

                                        Mass  =  Moles × M.mass

Putting values,

                                        Mass  =  0.1 mol × 61.83 g.mol⁻¹

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Flask used to prepare this solution is called as Volumetric flask. Take 2 L volumetric flask, add 6.183 g of Boric acid and fill it to the mark with distilled water.

7 0
2 years ago
If 35.50 cm3 of a NaOH solution are required for the complete neutralization of a 25.00cm3 sample of 0.200mol dm-3 H2SO4, what i
Morgarella [4.7K]
In this question, you are given the NaOH volume but asked for concentration. 
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:

OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
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2 years ago
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2 years ago
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In this case, the number 40.00 has four figures but only two of them are significant 40, this is because you haven't got any more decimals than the first zero.

If you have a case with zeros in front, you take to the first non zero digits.

For example, 0.071004 you wold express as 0.071 and those 7, and 1 are the significant ones.

4 0
2 years ago
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