Answer: d. More than 6.5 grams of copper (II) is formed, and some copper chloride is left in the reaction mixture.
Explanation: 
As can be seen from the chemical equation, 2 moles of aluminium react with 3 moles of copper chloride.
According to mole concept, 1 mole of every substance weighs equal to its molar mass.
Aluminium is the limiting reagent as it limits the formation of product and copper chloride is the excess reagent as (14-7.5)=6.5 g is left as such.
Thus 54 g of of aluminium react with 270 g of copper chloride.
1.50 g of aluminium react with=
of copper chloride.
3 moles of copper chloride gives 3 moles of copper.
7.5 g of copper chloride gives 7.5 g of copper.
Actually the strength
of London dispersion forces highly depend on the total number of electrons and
the area in which they are spread. We can see clearly that iodine will have the
strongest LDF's, and hence, have the highest boiling point (and melting point).
This is also the reason why iodine is a solid at room temperature, bromine is liquid
and chlorine and fluorine are gases.
Answer:
<span>Fluorine (F2)</span>
Answer:
2.49*10⁻¹² mol
Explanation:
Use Avogadro's Number for this equation (6.022*10²³). Divide Avogrado's by the number of atoms you have to find moles. You are answer should be 2.49*10⁻¹² mol.
Answer:
2HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)
Explanation:
HCl(aq) + Na2SO3(aq) —> NaCl(aq) + H2SO3(aq)
Let us balance the equation. This is illustrated below:
There are 2 atoms of Na on the left side of the equation and 1atom on the right side. It can be balance by putting 2 in front of NaCl as shown below:
HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)
Now, we have 2 atoms of Cl on the right side and 1 atom on the left side. Thus, it can be balance by putting 2 in front of HCl as shown below:
2HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)
A careful look at the equation proved that the equation is balanced as the numbers of the different atoms of the element on both side of the equation are the same.
