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lina2011 [118]
2 years ago
10

30. how many grams of boric acid, b(oh)3 (fm 61.83), should be used to make 2.00 l of 0.050 0 m solution? what kind of fl ask is

used to prepare this solution?

Chemistry
1 answer:
grigory [225]2 years ago
7 0

Answer:

             Mass  =  6.183 g

Solution:

Step 1: Calculate number of moles of Boric acid using following formula,

                                        Molarity  =  Moles ÷ Volume

Solving for Moles,

                                        Moles  =  Molarity × Volume

Putting Values,

                                        Moles  =  0.05 mol.L⁻¹ × 2.0 L

                                        Moles  =  0.1 mol

Step 2: Calculate Mass of Boric Acid using following formula,

                                        Moles  =  Mass ÷ M.mass

Solving for Mass,

                                        Mass  =  Moles × M.mass

Putting values,

                                        Mass  =  0.1 mol × 61.83 g.mol⁻¹

                                        Mass  =  6.183 g

Flask used to prepare this solution is called as Volumetric flask. Take 2 L volumetric flask, add 6.183 g of Boric acid and fill it to the mark with distilled water.

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How many ATP are produced from a fatty acid that is 14 carbons long?
fenix001 [56]

Answer:

92 ATP

Explanation:

Fatty acid oxidation results in the formation of large number of ATP molecules. Three important process of fatty acid are activation of the fatty acid, beta oxidation and entry of acetyl CoA in Krebs cycle.

14 carbon fatty acid is Miristic acid. The complete oxidation of Miristic acid results in the formation of 7 acetyl CoA + 6NADH and 6FADH_2

1 Acetyl CoA gives 10 molecules of ATP then 7 acetyl CoA gives 70 molecules of ATP.

1NADH = 2.5 ATP, 6NADH = 15 ATP.

1FADH_2 = 1.5 ATP, 6FADH_2 = 9 ATP.

2 ATP has been consumed in the activation of fatty acid.

Total ATP = 70+15+9-2

=92 ATP.

Thus, the total ATP generated from the oxidation of 14 carbon fatty acid is 92.

3 0
2 years ago
Which correctly summarizes the trend in electron affinity?it tends to be very high for group 2.it tends to be more negative acro
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4 0
2 years ago
Read 2 more answers
A 0.1153-gram sample of a pure hydrocarbon was burned in a C-H combustion train to produce 0.3986 gram of CO2and 0.0578 gram of
Mars2501 [29]

<u>Answer:</u> The mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=0.3986g

Mass of H_2O=0.0578g

Mass of sample = 0.1153 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.3986 g of carbon dioxide, \frac{12}{44}\times 0.3986=0.1087g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.0578 g of water, \frac{2}{18}\times 0.0578=0.0066g of hydrogen will be contained.

To calculate the percentage composition of a substance in sample, we use the equation:

\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of sample}}\times 100      ......(1)

  • <u>For Carbon:</u>

Mass of sample = 0.1153 g

Mass of carbon = 0.1087 g

Putting values in equation 1, we get:

\%\text{ composition of carbon}=\frac{0.1087g}{0.1153g}\times 100=94.27\%

  • <u>For Hydrogen:</u>

Mass of sample = 0.1153 g

Mass of hydrogen = 0.0066 g

Putting values in equation 1, we get:

\%\text{ composition of hydrogen}=\frac{0.0066g}{0.1153g}\times 100=5.72\%

Hence, the mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.

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Answer:

Explanation:

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let the mass of granite = m

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heat lost = mass x specific heat x drop in temperature

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heat gained by water

= 3000 x 4.186 x (20.45- 20)

heat lost by granite = heat gained by water

m x .79 x 59.55  =  3000 x 4.186 x .45

m = 120.12 g .

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