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bogdanovich [222]
2 years ago
5

If you were to perform the reaction KCl (s)→K+ (g)+ Cl−(g), would energy be absorbed or released? Lattice Energies for Some Ioni

c Compounds Compound Lattice Energy (kJ/mol) Compound Lattice Energy (kJ/mol) LiF 1030 MgCl2 2326 LiCl 834 SrCl2 2127 LiI 730 NaF 910 MgO 3795 NaCl 788 CaO 3414 NaBr 732 SrO 3217 NaI 682 KF 808 ScN 7547 KCl 701 KBr 671 CsCl 657 CsI 600 Drag the appropriate labels to their respective targets.
Chemistry
1 answer:
lina2011 [118]2 years ago
6 0

Answer:

Energy would be absorbed.

Explanation:

Lattice energy is defined as the energy required to break apart an ionic solid and convert its component atoms into gaseous ions. That is what you're doing in:

KCl (s) → K⁺(g) + Cl⁻(g)

The energy you require to obtain this reaction is 701 kJ/mol. As the value is positive, <em>energy would be absorbed.</em>

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I hope it helps!

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A common way of initiating certain chemical reactions with light involves the generation of free halogen atoms in solution. if δ
STatiana [176]

Answer: The longest wavelength of light that will produce free chlorine atoms in solution is 493 nm.

Explanation:

Cl_2\overset{h\nu}\rightarrow Cl^-,Delta H_{rxn}=242.8kJ/mol

Energy required to produce free chlorine atoms from one mole of chlorine gas :

= 242.8kJ = 242.8\times 1000=242800 Joules (1kJ=1000J)

1 mole = 6.022\times 10^{23} molecules

For 6.022\times 10^{23} molecules = 242,800 Joules

For one molecule of chlorine gas =  \frac{242800 Joules/mol}{6.022\times 10^{23} mol^{-1}}=40,318.83\times 10^{-23}Joules

According to photoelectric equation:

E=h\nu=\frac{hc}{\Lambda }

E = Energy of the photon of light used to produce free chlorine atoms

\nu= frequency of the light used to produce free chlorine atoms

h = Planck's constant =6.626\times 10^{-34}J.s, c = speed of light=3\times 10^8 m/s

\lambda = wavelength of the light used to produce free chlorine atoms

40,318.83\times 10^{-23}J=\frac{hc}{\Lambda }=\frac{6.626\times 10^{-34} J.s\times 3\times 10^8 m/s}{\lambda }

\lambda=0.0004930203\times 10^{-3} m=493.0203\times 10^{-9} m=493 nm

The longest wavelength of light that will produce free chlorine atoms in solution is 493 nm.

5 0
2 years ago
Draw the structures of organic compounds A and B. Indicate stereochemistry where applicable The starting material is ethyne, a c
k0ka [10]

Answer:

See explanation below

Explanation:

In this case we have the starting reactant which is the ethine, In the first step reacts with NaNH₂, a strong base. This base will substract the hydrogen from one of the carbon of the ethine, and form a carbanion. This will react with the propane bromide, displacing the bromine and forming a 5 carbon chain with the triple bond on the carbon 1 and 2.

In the second step, reacts with the lindlar catalyst to do a reduction, and form a double bond between carbon 1 and 2. In essence, compound A is similar to compound B.

Finally B reacts with water in acid and makes a addition reaction, and form an alcohol.

The whole process can be seen in the picture below.

Hope this helps

3 0
2 years ago
For the reaction c + 2h2 → ch4, how many moles of hydrogen are required to produce 10 moles of methane, ch4?
r-ruslan [8.4K]
                                                 C+2H2 -------> CH4   
from reaction                              2 mol           1 mol
from the problem                       x mol           10 mol

x=2*10/1 = 20 mol

Answer: 20 mol of H2.

4 0
2 years ago
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Vilka [71]

Answer:

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3 0
2 years ago
The balanced reaction equation for combustion of heptane, C 7 H 16 , is C 7 H 16 + 11 O 2 ⟶ 7 CO 2 + 8 H 2 O If the reaction pro
Scorpion4ik [409]

Answer:

1) There were 7.65 grams of heptane burned

2) There reacted 38.94 grams of HCl

Explanation:

<em>1) The combustion of heptane</em>

Step 1: Data given

Mass of CO2 = 23.5 grams

Molar mass of CO2 = 44.01 g/mol

Step 2: The balanced equation:

C7H16  + 11O2 ⟶ 7CO2 + 8H2O

Step 3: Calculate moles of CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 23.5 grams / 44.01 g/mol

Moles CO2 = 0.534 moles

Step 4: Calculate moles heptane

For 1 mole of Heptane , we need 11 moles of O2 to produce 7 moles of CO2 and 8 moles of H2O

For 0.534 moles of CO2 we have 0.534/7 = 0.0763 moles of  heptane

Step 5: Calculate mass of heptane

Mass of heptane = moles heptane * molar mass heptane

Mass heptane = 0.0763 moles * 100.21 g/mol

Mass heptane = 7.65 grams

<em></em>

<em>2) The reaction of limestone with hydrochloric acid</em>

Step 1: Data given

Mass of CO2 = 23.5 grams

Step 2: The balanced equation:

CaCO3 + 2HCl ⟶ CaCl2 + CO2 + H2O

Step 3: Calculate moles of CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 23.5 grams / 44.01 g/mol

Moles CO2 = 0.534 moles

Step 4: Calculate moles of HCl

For 1 mol of CaCO3 we need 2 moles of HCl to produce 1 mol of CaCl2, 1 mol of CO2 and 1 mol of H2O

For 0.534 moles of CO2 we have 2*0.534 = 1.068 moles of HCl

Step 5: Calculate mass of HCl

Mass HCl = moles HCl * molar mass HCl

Mass HCl = 1.068 moles * 36.46 g/mol

Mass HCl = 38.94 grams

3 0
2 years ago
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