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trasher [3.6K]
2 years ago
14

How many moles of lithium are present in a sample that contains 2.45x10^87 formula units of Li2SO4?​

Chemistry
1 answer:
ddd [48]2 years ago
3 0

The answer is: 8.14·10⁶³ moles of lithium are present.

N(Li₂SO₄) = 2.45·10⁸⁷; number of formula units of lithium sulfate.

n(Li₂SO₄) = N(Li₂SO₄) ÷ Na.

n(Li₂SO₄) = 2.45·10⁸⁷ ÷ 6.022·10²³ 1/mol.

n(Li₂SO₄) = 4.07·10⁶³ mol; amount of lithium sulfate

In one molecule of lithium sulfate, there are two atoms of lithium.

n(Li₂SO₄) : n(Li) = 1 : 2.

n(Li) = 2 · 4.07·10⁶³ mol.

n(Li) = 8.14·10⁶³ mol; amount of lithium atoms.

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Write an equation that represents the action in water of rubidium hydroxide as an Arrhenius base.
Anika [276]

Answer:

RbOH  → Rb⁺ +  OH⁻

As the hydroxide can gives the OH⁻ in water, it is considered as an Arrhenius's base

Explanation:

Arrhenius theory states that a compound is considered a base, if the compound can generate OH⁻ ions in aqueous solution.

Our compound is the RbOH.

When it is put in water, i can dissociate like this:

RbOH  → Rb⁺ +  OH⁻

As the hydroxide can gives the OH⁻ in water, it is considered as an Arrhenius's base

3 0
2 years ago
A 1.850 g mixture of SrCO3 and SrO is heated. The SrCO3 decomposes to SrO and CO2. What was the mass percentage of SrCO3 in the
Oliga [24]
<span>decomposition of SrCO3 to SrO and CO2 =change in mass

 moles of CO2 =(1.850 g - 1.445 g). 
</span>Mass of <span>C<span>O2</span></span><span> in mixture: 1.850-1.445 = 0.405g
</span>0.405g/44.01 g/mol <span>C<span>O2</span></span><span> = 0.0092 moles </span><span>C<span>O2</span></span><span>.
</span>ratio of <span>C<span>O2</span></span><span> to SrO in Sr</span><span>C<span>O3</span></span><span> is 1:1
</span><span> mass ratio = 1.358/1.850 = 0.7341, </span>
or 73.41% Sr<span>C<span>O3</span></span><span>.
</span>hope this helps
5 0
2 years ago
Read 2 more answers
Which is the correct Lewis structure for fluorine, which is a group 7A element?
Yuliya22 [10]
The correct Lewis structure for Fluorine is A.
4 0
2 years ago
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The pressure and temperature inside a bike tire is 10 atm and 10k respectively. What will the pressure become in the tire when t
igomit [66]

Answer:

P_2=20atm

Explanation:

Hello,

In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior as a directly proportional relationship:

\frac{P_1}{T_1}= \frac{P_2}{T_2}

Thus, we solve for the final pressure P2 to obtain it as shown below:

P_2=\frac{P_1T_2}{T_1}=\frac{10atm*20K}{10K} \\\\P_2=20atm

Hence, we notice that the temperature doubles as well as the pressure.

Best regards.

3 0
2 years ago
A boy with pneumonia has lungs with a volume of 1.9 L that fill with 0.080 mol of air when he inhales. When he exhales, his lung
mariarad [96]

<u>Answer:</u> The number of moles of gas remaining in the lungs is 0.063 moles

<u>Explanation:</u>

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the initial volume and number of moles

V_2\text{ and }n_2 are the final volume and number of moles

We are given:

V-1=1.9L\\n_1=0.080mol\\V_2=1.5L\\n_2=?

Putting values in above equation, we get:

\frac{1.9}{0.080}=\frac{1.5}{n_2}\\\\n_2=\frac{1.5\times 0.080}{1.9}=0.063

Hence, the number of moles of gas remaining in the lungs is 0.063 moles

8 0
2 years ago
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