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padilas [110]
2 years ago
15

A boy with pneumonia has lungs with a volume of 1.9 L that fill with 0.080 mol of air when he inhales. When he exhales, his lung

volume decreases to 1.5 L. Enter the number of moles of gas that remain in his lungs after he exhales. Assume constant temperature and pressure. g
Chemistry
1 answer:
mariarad [96]2 years ago
8 0

<u>Answer:</u> The number of moles of gas remaining in the lungs is 0.063 moles

<u>Explanation:</u>

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the initial volume and number of moles

V_2\text{ and }n_2 are the final volume and number of moles

We are given:

V-1=1.9L\\n_1=0.080mol\\V_2=1.5L\\n_2=?

Putting values in above equation, we get:

\frac{1.9}{0.080}=\frac{1.5}{n_2}\\\\n_2=\frac{1.5\times 0.080}{1.9}=0.063

Hence, the number of moles of gas remaining in the lungs is 0.063 moles

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What is the percent yield of this reaction if 22.o g of Mgl2 is produced by the reaction of 25.0 g of Mg with 25.0 g of l2?
expeople1 [14]

% yield = 80.719

<h3>Further explanation</h3>

Given

22.0 g of Mgl₂

25.0 g of Mg

25.0 g of l₂

Required

The percent yield

Solution

Reaction

Mg + I₂⇒ MgI₂

mol Mg = 25 g : 24.305 g/mol = 1.029

mol I₂ = 25 g : 253.809 g/mol = 0.098

Limiting reactant = I₂

Excess reactant = Mg

mol MgI₂ based on I₂, so mol MgI₂ = 0.098

Mass MgI₂ (theoretical):

= mol x MW

= 0.098 x 278.114

= 27.255 g

% yield = (actual/theoretical) x 100%

% yield = (22 / 27.255) x 100%

% yield = 80.719

8 0
1 year ago
The nuclear equation is incomplete. Superscript 239 Subscript 94 Baseline P u + Superscript 1 Subscript 0 Baseline n yields Supe
Likurg_2 [28]

Answer:

The correct option is the first option

Explanation:

The equation described in the question is shown below

²³⁹₉₄Pu +¹₀n ⇒ ¹⁰⁰₄₀Zr + blank + 2¹₀n

This equation is a nuclear fission because it involves the splitting of a heavy nucleus, Plutonium (Pu), into smaller nuclei, Zirconium (Zr) and an unknown nuclei.

The law of conservation of matter states that matter can neither be created nor destroyed hence in other to get the missing atom, we must know the total number of subscripts (mass number) and superscripts (atomic number) on both sides.

The total mass number on the reactant side is 239 + 1 = 240

The total atomic number on the reactant side is 94 + 0 = 94

While, The total mass number on the product side is 100 + 2(1) = 102

The total atomic number on the product side is 40 + 2(0) = 40

To determine <u>the missing atom</u>, you subtract the the total atomic number of the product from that on the reactant side; 94 - 40 = 54

The <u>atom with the atomic number 54 is Xenon</u>,

To <u>determine the mass number</u> of the xenon isotope involved, you subtract the the total mass number of the product from that on the reactant side; 240 - 102 = 138.

Hence, the particle that completes the equation is ¹³⁸₅₄Xe, the first option

5 0
2 years ago
Which of these correctly defines the pOH of a solution? the log of the hydronium ion concentration the negative log of the hydro
Likurg_2 [28]

Answer : The correct option is, the negative log of the hydroxide ion concentration.

Explanation :

pOH : It is defined as the negative logarithm of hydroxide ion concentration. It is a measure of the alkalinity of the solution.

Formula used :

pOH=-log[OH^-]

[OH^-] is the concentration of OH^- ions.

When pOH is less than 7, the solution is alkaline.

When pOH is more than 7, the solution is acidic.

When pOH is equal to 7, the solution is neutral.

4 0
2 years ago
Read 2 more answers
A gas occupies 72.1 at stp. At what temperature would the gas occupy 85.9 L at a pressure of 93.6 kPa?
Alika [10]

Answer:

328.1 K.

Explanation:

  • To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT</em>.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in.

  • If n is constant, and have two different values of (P, V and T):

<em>P₁V₁T₂ = P₂V₂T₁</em>

<em></em>

P₁ = 1.0 atm (standard P), V₁ = 72.1 L, T₁ = 25°C + 273 = 298 K (standard T).

P₂ = 93.6 kPa = 0.924 atm, V₂ = 85.9 L, T₂ = ??? K.

<em>T₂ = P₂V₂T₁/P₁V₁ = </em>(0.924 atm)(85.9 L)(298 K)/(1.0 atm)(72.1 L) <em>= 328.1 K.</em>

<em></em>

4 0
2 years ago
Solve without using a calculator. Substance ab2 is 60.0% a by mass. What is the percent a by mass for substance ab?
Orlov [11]

The percent A by mass for substance AB =<u> 75%</u>

<h3>Further explanation</h3>

Proust states the Comparative Law that compounds are formed from elements with the same Mass Comparison, so that compounds have a fixed composition of elements

Empirical formula is the mole ratio of compounds forming elements.

From Substance AB₂ is 60.0% A by mass.

Let's say that AB₂ mass = 100 gram, then

mass A = 60 gram

mass B = 40 gram : 2 (coefficient in compound AB₂ = 2) = 20 gram

In compound AB:

Total mass = mass A + mass B

Total mass = 60 + 20 grams = 80 grams

Then the percentage of compound A = (60: 80) = 75%

<h3>Learn more</h3>

Grams of KO₂ needed to form O₂

brainly.com/question/2823257

Keywords : percent mass, substance

#LearnwithBrainly

5 0
2 years ago
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