Answer:

Explanation:
Hello,
In this case, since calcium hydroxide a strong base, its dissociation will completely result in both calcium and hydroxyl ions:

Thus, the concentration of hydroxyl ions equals that of the calcium hydroxide, with which we could compute the pOH as shown below:
![pOH=-log([OH^-]}=-log(0.0012)\\\\pOH=2.92](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%7D%3D-log%280.0012%29%5C%5C%5C%5CpOH%3D2.92)
Now, the pH and the pOH are related by:

Hence, the pH finally results:

Best regards.
Here, the three different notation of the p-orbital in different sub-level have to generate
The value of azimuthal quantum number (l) for -p orbital is 1. We know that the magnetic quantum number
depends upon the value of l, which are -l to +l.
Thus for p-orbital the possible magnetic quantum numbers are- -1, 0, +1. So there will be three orbitals for p orbitals, which are designated as
,
and
in space.
The three p-orbital can be distinguish by the quantum numbers as-
For 2p orbitals (principal quantum number is 2)
1) n = 2, l = 1, m = -1
2) n = 2, l = 1, m = 0
3) n = 2, l = 1, m = +1
Thus the notation of different p-orbitals in the sub level are determined.
Answer:
See explanation
Explanation:
% optical purity = specific rotation of mixture/specific rotation of pure enantiomer * 100/1
specific rotation of mixture = 23°
specific rotation of pure enantiomer = 61°
Hence;
% optical purity = 23/61 * 100 = 38 %
More abundant enantiomer = 100% - 38 % = 62%
Hence the pure (S) carvone is (-) 62° is the more abundant enantiomer.
Enantiomeric excess = 62 - 50/50 * 100 = 24%
Hence
(R) - carvone = 38 %
(S) - carvone = 62%
Answer:
Explanation:
q= mc theta
where,
Q = heat gained
m = mass of the substance = 670g
c = heat capacity of water= 4.1 J/g°C
theta =Change in temperature=(
66-25.7)
Now put all the given values in the above formula, we get the amount of heat needed.
q= mctheta
q=670*4.1*(66-25.7)
=670*4.1*40.3
=110704.1