Answer:
The coefficients are 1, 3, 1, 3
Explanation:
The equation;
AlCl3 + NaOH → Al(OH)3 + NaCl
can be balanced by using the coefficients 1, 3, 1, 3, such that the balanced equation will be;
AlCl3 + 3NaOH → Al(OH)3 + 3NaCl
Chemical equations needs to be balanced so as to follow the law of conservation of mass. This occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side.
Answer:
The final temperature of water is 54.5 °C.
Explanation:
Given data:
Energy transferred = 65 Kj
Mass of water = 450 g
Initial temperature = T1 = 20 °C
Final temperature= T2 = ?
Solution:
First of all we will convert the heat in Kj to joule.
1 Kj = 1000 j
65× 1000 = 65000 j
specific heat of water is 4.186 J /g. °C
Formula:
q = m × c × ΔT
ΔT = T2 - T1
Now we will put the values in Formula.
65000 j = 450 g × 4.186 J /g. °C × (T2 - 20°C )
65000 j = 1883.7 j /°C × (T2 - 20°C )
65000 j/ 1883.7 j /°C = T2 - 20°C
34.51 °C = T2 - 20°C
34.51 °C + 20 °C = T2
T2 = 54.5 °C
Answer: 91.73g of NaCl
Explanation:
First, we solve for the number of moles of F2 using the ideal gas equation
V = 12L
P = 1.5 atm
T = 280K
R = 0.082atm.L/mol/K
n =?
PV = nRT
n = PV /RT
n = (1.5x12)/(0.082x280)
n = 0.784mol
Next, we convert this mole ( i.e 0.784mol) of F2 to mass
MM of F2 = 19x2 = 38g/mol
Mass conc of F2 = n x MM
= 0.784 x 38 = 29.792g
Equation for the reaction is given below
F2 + 2NaCl —> 2NaF + Cl2
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass conc. of NaCl from the equation = 2 x 58.5 = 117g
Next, we find the mass of NaCl that reacted with 29.792g of F2.
From the equation,
38g of F2 redacted with 117g of NaCl.
Therefore, 29.792g of F2 will react with Xg of NaCl i.e
Xg of NaCl = (29.792 x 117)/38
= 91.73g
Therefore, 91.73g of NaCl reacted with f2
Answer:
Before we start answering, the appropiate equation for the energy of an ionic bond should be written:

Where A1+, B2- are the charges of the ions and Ro is the interionic distance (the sum of the radii of the anion and cation). C is a constant depending on the ionic structure.
Explanation:
Examining the equation above, we have the following scenarios:
a) Doubling the radius of A1 would mean a decrease on the energy of the ionic bond.
b) Tripling the charge of A1 would also triple the energy of the ionic bond
c)Doubling the charges on A1 and B2 would quadruple the energy of the ionic bond.
d)Decreasing the radii of A1 and B2 to half their original values would double the energy of the energy bond.
Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Explanation:
First we have to calculate the moles of diethyl ether

As, 1 mole of diethyl ether require heat = 26.5 kJ
So, 1.01 moles of diethyl ether require heat = 
Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether