N = 1
l = from 0 to (n-1)
ml = -1... + 1
ms = 1/2 or -1/2
eg = 2s
n = 2, m = 0, n = 0
s = 1/2, -1/2
hope this help
Answer:
The molecular formula of the compound is
.
Explanation:
Let consider that given percentages are mass percentages, so that mass of each element are determined by multiplying molar massof the organic acid by respective proportion. That is:
Carbon


Hydrogen


Oxygen


Now, the number of moles (
), measured in moles, of each element are calculated by the following expression:

Where:
- Mass of the element, measured in grams.
- Molar mass of the element, measured in grams per mol.
Carbon (
,
)


Hydrogen (
,
)


Oxygen (
,
)


For each mole of organic acid, there are 7 moles of carbon, 6 moles of hydrogen and 2 moles of oxygen. Hence, the molecular formula of the compound is:

<h3>
Answer:</h3>
a) LiClO4 - Strong electrolyte
b) HClO -Weak electrolyte
c) CH3CH2CH2OH - Non-electrolyte
d) HClO3 - Strong electrolyte
e) CuSO4 -strong electrolyte
f) C12H22O11-Non-electrolyte
<h3>
Explanation:</h3>
- An electrolyte is a substance in an aqueous or molten form which is decomposed by passing an electric current through it. Electrolytes ionize to ions which are responsible for the conduction of electric charge.
- Non-electrolytes are substances that do not ionize into cations and anions and thus do not conduct. They include molecular compounds such as gases.
- Electrolytes may be weak or strong depending on the level of ionization.
- Weak electrolytes are those that undergo partial ionization while strong electrolytes completely ionize.
Answer:
Bi2(SO4)3
Explanation:
Bismuth(iii) sulfate is an ionic compound therefore, their is transfer of electron. Ionic compound has both cations and anions. The cations is positively charged ion while the anions is negatively charged ions. The cations loses electron to become positively charged while the anions gains electron to become negatively charged.
From the compound above, Bismuth(iii) sulfate the cations will be Bismuth ion which loses 3 electrons. The anions is the sulfate ion (S04)2- with a -2 charge.
The chemical formula can be computed from the charge configuration as follows
Bi3+ and (SO4)2-
cross multiply the charges living the sign behind to get the chemical formula
Bi2(SO4)3
Note the final chemical formula, the numbers are sub scripted