First, we assume that helium behaves as an ideal gas such that the ideal gas law is applicable.
PV = nRT
where P is pressure, V is volume, n is number of moles, R is universal gas constant, and T is temperature. From the equation, if n, R, and T are constant, there is an inverse relationship between P and V. From the given choices, the container with the greatest pressure would be the 50 mL.
Although the process varies slightly from one material to another, the general process is as follows:
1) Choose an appropriate container for the solid. This may be a petri dish or a beaker in which you want to prepare the solution of the solid or any other lab equipment.
2) Place the container on a mass balance, then turn the balance on. The mass balance will automatically zero-out the mass of the container, so that any mass that you add on the container will be the mass of the solid. Alternatively, you may first measure the mass of the empty container alone.
3) Add the solid using a lab spatula. The solid should be added more slowly when the reading on the scale comes close to the desired value.
4) Remove the container from the mass balance after the desired amount of solid has been added.
<h3>Answer:</h3>
Option-C: HCl + H₂O → H₃O⁺ + Cl⁻
Explanation:
Bronsted-Lowery concept of Acid and Base defines Acid as that specie which tends to donate H⁺ (Hydrogen Ion) and bases are those species which accepts H⁺ from Acids.
In selected option, HCl is reacting as Acid as it donates H⁺ to water (lowery bronsted base).
Also, the correspong acid is converted into conjugate base (i.e. Cl⁻) and base is converted into conjugate acid (i.e. H₃O⁺)
Answer:
2,019 km
Explanation:
Step 1: Given data
Distance traveled by the car (D): 1,255 mi
Step 2: Convert the distance traveled by the car to kilometers
To convert one unit into another, we use a conversion factor. In this case, the appropriate conversion factor between miles and kilometers is 1 mile = 1.609 km. The distance traveled by the car, in kilometers, is:
D = 1,255 mi × (1.609 km/1 mi) = 2,019 km
The concentration of a solution is the number of moles of solute per fixed volume of solution.
Concentration (C) = number of moles of solute (n) / volume of the solution (v)
we have to find the volume of the solution when 36.0 g of Ca(OH)₂ is added to water to make a solution of concentration 0.530 M
mass of Ca(OH)₂ added - 36.0 g
number of moles of Ca(OH)₂ - 36.0 g / 74.1 g/mol = 0.486 mol
we know the concentration of the solution prepared and the number of moles of Ca(OH)₂ added, substituting these values in the above equation, we can find the volume of the solution
C = n/v
0.530 mol/L = 0.486 mol / V
V = 0.917 L
answer is 0.917 L