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alexandr402 [8]
1 year ago
8

In an experiment, the density of an unknown liquid was calculated to be 0.78 g/ml. if the accepted value is 0.75 g/ml, calculate

the percent error made.
Chemistry
1 answer:
Vikki [24]1 year ago
6 0
Percentage error is the relative error your measured value is from the true or accepted value. The formula for percentage error is written below:

Percentage error = |True Value - Measured Value|/True Value   * 100
Percentage error = |0.75 g/mL - 0.78 g/mL|/0.75 g/mL  * 100
Percentage error = 4%
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Which of the following statements is true about the following reaction?
MAVERICK [17]

The correct reaction equation is:

3NaHCO_{3} (aq) + C_{6}H_{8}O_{7} (aq) \rightarrow 3CO_{2} (g) + 3H_{2}O (l) + Na_{3}C_{6}H_{5}O_{7} (aq)

Answer:

b) 1 mole of water is produced for every mole of carbon dioxide produced.

Explanation: <u>CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.</u>

a) <u>22.4 L of CO_{2} gas</u> is produced only when <u>\frac{22.4}{3} L of  C_{6}H_{8}O_{7}</u> is reacted with 22.4 L of NaHCO_{3}. So it is wrong.

b) Since in the chemical equation the stoichiometric coefficient of CO_{2}  and H_{2}O are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. <u>Therefore it is correct option.</u>

c)  6.02\times 10^{23} molecules is equal 1 mole of Na_{3}C_{6}H_{5}O_{7} if produced then 3 moles of NaHCO_{3} is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of H_{2}O (<em>Molecular Weight of water is 18 g</em>) is produced when 3 moles of NaHCO_{3} is used but in this option only one mole of NaHCO_{3} is given. So it is wrong.

8 0
2 years ago
Read 2 more answers
A 60.2-ml sample of hg (density = 13.6 g/ml) contains how many atoms of hg?
Over [174]
Density is calculated using the following rule:
density = mass / volume
therefore:
mass = density * volume
mass of Hg = 13.6 * 60.2 = 818.72 grams

From the periodic table:
molar mass of Hg = 200.59 grams

number of moles = mass / molar mass
number of moles of Hg = 818.72 / 200.59 = 4.08 moles

each mole contains Avogadro's number of atoms.
Therefore,
number of atoms in the given sample = 4.08 * 6.022 * 10^23
                                                            = 2.456976 * 10^24 atoms
6 0
1 year ago
A reaction produces a gas, which is collected in a glass cylinder. When a glowing splint is placed inside the container, it burn
Gnesinka [82]

Answer:

true

Explanation:

5 0
2 years ago
Two species, A and B, are separated on a 2.00 m long column which has 5.000 x 103 plates when the flow rate is 15.0 mL/min. A sp
sergiy2304 [10]

Explanation:

The given data is as follows.

         t_{m} = 30.0 sec,     t_{r1} = 5 min = 5 \times 60 sec = 300 sec

         t_{r2} = 12.0 min = 12 \times 60 sec = 720 sec

Formula for adjusted retention time is as follows.

      t'_{r} = t_{r} - t_{m}

                 = 300 sec - 30.0 sec

                 = 270 sec

   t'_{r2} = 720 sec - 30 sec

                            = 690 sec

Formula for relative retention (\alpha) is as follows.

          \alpha = \frac{t'_{r2}}{t'_{r1}}

                     = \frac{690 sec}{270 sec}

                     = 2.56

Thus, we can conclude that the relative retention is 2.56.

4 0
2 years ago
25.0 ml of a 6.0 m hno3 stock solution is diluted using water to 100 ml. How many moles of hno3 are present in the dilute soluti
lana66690 [7]

Answer:

The answer to your question is: 6 moles of HNO₃

Explanation:

Data

Volume = 25 ml

Concentration = 6 M HNO₃

Diluted 100 ml

Formula

Molarity = # moles / volume

# of moles = Volume x Molarity

Process

# of moles = 0.10 x 6

                 = 6 moles

6 0
2 years ago
Read 2 more answers
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