<u>Answer:</u> The volume of CO formed is 254.43 L.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of = 444 g
Molar mass of = 170.73 g/mol
Putting values in above equation, we get:
For the given chemical reaction:
By stoichiometry of the reaction:
1 mole of nickel tetracarbonyl produces 4 moles of carbon monoxide.
So, 2.60 moles of nickel tetracarbonyl will produce = of carbon monoxide.
Now, to calculate the volume of the gas, we use ideal gas equation, which is:
PV = nRT
where,
P = Pressure of the gas = 752 torr
V = Volume of the gas = ? L
n = Number of moles of gas = 10.4 mol
R = Gas constant =
T = Temperature of the gas =
Putting values in above equation, we get:
Hence, the volume of CO formed is 254.43 L.