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Umnica [9.8K]
2 years ago
11

Identify the following redox reactions by type. Check all that apply. (a) Fe + H2SO4 → FeSO4 + H2 combination decomposition disp

lacement disproportionation (b) S + 3F2 → SF6 combination decomposition displacement disproportionation (c) 2CuCl → Cu + CuCl2 combination decomposition displacement disproportionation (d) 2Ag + PtCl2 → 2AgCl + Pt combination decomposition displacement disproportionation
Chemistry
1 answer:
EastWind [94]2 years ago
7 0

Answer :

(a) displacement reaction

(b) combination reaction

(c) disproportionation reaction

(d) displacement reaction

Explanation :

(a) The given balanced chemical reaction is,

Fe+H_2SO_4\rightarrow FeSO_4+H_2

This reaction is a single replacement reaction or displacement in which the the more reactive element (Fe) replace the less reactive element (H).

(b) The given balanced chemical reaction is,

S+3F_2\rightarrow SF_6

This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or single product.

(c) The given balanced chemical reaction is,

2CuCl_2\rightarrow Cu+CuCl_2

This reaction is a disproportionation reaction in which the chemical species gets oxidized and reduced simultaneously.  It is also considered as a redox reaction.

(d) The given balanced chemical reaction is,

2Ag+PtCl_2\rightarrow 2AgCl+Pt

This reaction is a single replacement reaction or displacement in which the the more reactive element (Ag) replace the less reactive element (Pt).

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A 0.4657 g sample of a pure soluble bromide compound is dissolved in water, and all of the bromide ion is precipitated as AgBr b
Yanka [14]

Answer:

The mass percentage of bromine in the original compound is 81,12%

Explanation:

<u>Step 1: Calculate moles AgBr</u>

moles AgBr = mass AgBr / molar mass  AgBr

= 0.8878 g / 187.77 g/mol

= 0.00472812 moles AgBr

⇒

Since 1 mol AgBr contains 1 mol Br-

Then the amount of moles Br- in the original sample must also have  been 0.00472812 moles

<u>Step 2:</u> Calculating mass Br-

mass Br- = molar mass Br x moles  Br-

= 79.904 g/mol x 0.00472812 mol

= 0.377796 g Br-

⇒

There were 0.377796 g Br- in the original sample

<u>Step 3:</u> Calculating mass percentage Br-

⇒mass percentage  = actual mass Br- / total mass x 100%

% mass Br = 0.377796 g / 0.4657 g x 100  %

= 81.12%

7 0
2 years ago
What is the mass of 7.68 x 1024 molecules of phosphorus trichloride?
fiasKO [112]

Answer:

THE MASS OF 7.68 *10^24 MOLECULES OF PHOSPHORUS TRICHLORIDE IS 1746.25 g.

Explanation:

Molar mass of PCl3 = ( 31 + 35.5 *3) = 137.5 g/mol

At 7.68 * 10^24 molecules, how many number of mole is present?

6.03 * 10^23 molecules = 1 mole

7.68*10^24 molecules = x mole

x mole = 7.68 *10^24 molecules/ 6.03 *10^23

x mole = 1.27 *10 moles

x mole = 12.7 moles

Using mole = mass / molar mass

mass = mole * molar mass

mass = 12.7 moles * 137.5 g/mol

mass = 1746.25 g

Hence, the mass of 7.68 *10^24 molecules is 1746.25 g

3 0
2 years ago
Electrons in __________ bonds remain localized between two atoms. electrons in __________ bonds can become delocalized between m
dsp73

Electrons in sigma <span>bonds remain localized between two atoms. Sigma </span><span>bond results from the formation of </span><span>a molecular orbital </span><span>by the end to </span><span>end overlap of atomic </span>orbitals. Electrons<span> in pi</span> bonds can become delocalized between more than two atoms. Pi bonds result from the formation of molecular orbital by side to side overlap of atomic orbitals. 

 

<span> </span>

7 0
2 years ago
Which solution contains the largest number of moles of chloride ions?
elixir [45]
Molarity = number of moles of solute/liters of solution
number of moles of solute = molarity x liters of solution

Part (a): <span>30.00 ml of 0.100m Cacl2
number of moles of CaCl2 =  0.1 x 0.03 = 3x10^-3 moles
1 mole of CaCl2 contains 2 moles of chlorine, therefore 3x10^-3 moles of CaCl2 contains 6x10^-3 moles of chlorine

Part (b): </span><span>10.0 ml of 0.500m bacl2
number of moles of BaCl2 = 0.5 x 0.01 = 5x10^-3 moles
1 mole of BaCl2 contains 2 moles of chlorine, therefore 5x10^-3 moles of BaCl2 contains 10x10^-3 moles of chlorine

Part (c): </span><span>4.00 ml of 1.000m nacl
number of moles of NaCl = 1 x 0.004 = 0.004 moles
1 mole of NaCl contains 1 mole of chlorine, therefore 4x10^-3 moles of NaCl contains 4x10^-3 moles of chlorine

Part (d): </span><span>7.50 ml of 0.500m fecl3
number of moles of FeCl3 = 0.5 x 0.0075 = 3.75x10^-3 moles
1 mole of FeCl3 contains 3 moles of chlorine, therefore 3.75x10^-3 moles of FeCl3 contains 0.01125 moles of chlorine

Based on the above calculations, the correct answer is (d)</span>
5 0
2 years ago
Read 2 more answers
An ice cube with a volume of 45.0ml and a density of 0.9000g/cm3 floats in a liquid with a density of 1.36g/ml. what volume of t
Grace [21]

Answer : The volume of the cube submerged in the liquid is, 29.8 mL

Explanation :

First we have to determine the mass of ice.

Formula used :

\text{Mass of ice}=\text{Density of ice}\times \text{Volume of ice}

Given:

Density of ice = 0.9000g/cm^3=0.9000g/mL

Volume of ice = 45.0 mL

\text{Mass of ice}=0.9000g/mL\times 45.0mL

\text{Mass of ice}=40.5g

The cube will float when 40.5 g of liquid is displaced.

Now we have to determine the volume of the cube is submerged in the liquid.

\text{Volume of ice}=\frac{\text{Mass of liquid}}{\text{Density of liquid}}

\text{Volume of ice}=\frac{40.5g}{1.36g/mL}

\text{Volume of ice}=29.8mL

Thus, the volume of the cube submerged in the liquid is, 29.8 mL

5 0
2 years ago
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