Question

An ice cube with a volume of 45.0ml and a density of 0.9000g/cm3 floats in a liquid with a density of 1.36g/ml. what volume of the cube is submerged in the liquid

Answer 1

Answer : The volume of the cube submerged in the liquid is, 29.8 mL

Explanation :

First we have to determine the mass of ice.

Formula used :

$\text{Mass of ice}=\text{Density of ice}\times \text{Volume of ice}$

Given:

Density of ice = $0.9000g/cm^3=0.9000g/mL$

Volume of ice = 45.0 mL

$\text{Mass of ice}=0.9000g/mL\times 45.0mL$

$\text{Mass of ice}=40.5g$

The cube will float when 40.5 g of liquid is displaced.

Now we have to determine the volume of the cube is submerged in the liquid.

$\text{Volume of ice}=\frac{\text{Mass of liquid}}{\text{Density of liquid}}$

$\text{Volume of ice}=\frac{40.5g}{1.36g/mL}$

$\text{Volume of ice}=29.8mL$

Thus, the volume of the cube submerged in the liquid is, 29.8 mL