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2 years ago

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An ice cube with a volume of 45.0ml and a density of 0.9000g/cm3 floats in a liquid with a density of 1.36g/ml. what volume of t

he cube is submerged in the liquid

1 answer:

Grace [21]2 years ago

5 0

Answer : The volume of the cube submerged in the liquid is, 29.8 mL

Explanation :

First we have to determine the mass of ice.

Formula used :

$\text{Mass of ice}=\text{Density of ice}\times \text{Volume of ice}$

Given:

Density of ice = $0.9000g/cm^3=0.9000g/mL$

Volume of ice = 45.0 mL

$\text{Mass of ice}=0.9000g/mL\times 45.0mL$

$\text{Mass of ice}=40.5g$

The cube will float when 40.5 g of liquid is displaced.

Now we have to determine the volume of the cube is submerged in the liquid.

$\text{Volume of ice}=\frac{\text{Mass of liquid}}{\text{Density of liquid}}$

$\text{Volume of ice}=\frac{40.5g}{1.36g/mL}$

$\text{Volume of ice}=29.8mL$

Thus, the volume of the cube submerged in the liquid is, 29.8 mL

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1 year ago

what can you say about the average distance from the nuclease of an electron the 2's orbital as compared with a 3s orbital

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Answer:

A 3s orbital is at a greater average distance from the nucleus than a 2s orbital

Explanation:

As the principal quantum number n increases, the distance of the orbital from the nucleus increases. Hence if we consider the 2s and 3s orbitals, it is easy to see that the 3s orbital is at a greater distance from the nucleus than the 2s orbitals.

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2 years ago

In a lab, 33 g of potassium chloride is formed from 60.0 g of potassium chlorate decomposing. Calculate the theoretical yield an

Svetlanka [38]

Answer: The theoretical yield and percent yield for this experiment are 40 g and 82% respectively.

Explanation:

$2KClO_3\rightarrow 2KCl+3O_2$

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $(6.023\times 10^{23})$ of particles.

To calculate the moles:

$\text{Moles of potassium chloride}=\frac{\text{Mass of potassium chloride}}{\text{Molar mass of potassium chloride}}=\frac{33g}{74.5g/mole}=0.44moles$

$\text{Moles of potassium chlorate}=\frac{\text{Mass of potassium chlorate}}{\text{Molar mass of potassium chlorate}}=\frac{66g}{122.5g/mole}=0.54moles$

According to stochiometry:

2 moles of $KClO_3$ produce = 2 moles of $KCl$

0.54 moles of $KClO_3$ should produce = $\frac{2}{2}\times 0.54=0.54moles$ of $KCl$

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But Experimental yield is 33 g.

${\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%$

${\text {percentage yield}}=\frac{33g}{40g}\times 100\%=82\%$

The theoretical yield and percent yield for this experiment are 40 g and 82% respectively.

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1 year ago

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Answer:

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Explanation:

Hello,

In this case, given the reaction:

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1 year ago

it takes 151 kJ/mol to break an iodine-iodine single bond. calculate the maximum wavelength of light for which an iodine-iodine

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Answer:

The wavelength of light require to brake an single I-I bond is 7.92 × 10⁻⁷ m

Explanation:

Amount of energy required to break the one mole of iodine-iodine single bond = 151 KJ

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or

2.51 × 10⁻¹⁹ J

Formula:

E = hc / λ

h = planck's constant = 6.626 × 10⁻³⁴ js

c = speed of light = 3 × 10⁸ m/s

λ = wavelength

Solution:

E = hc / λ

λ = hc / E

λ = (6.626 × 10⁻³⁴ js × 3 × 10⁸ m/s ) / 2.51 × 10⁻¹⁹ J

λ = 19.878 × 10⁻²⁶ j .m / 2.51 × 10⁻¹⁹ J

λ = 7.92 × 10⁻⁷ m

6 0

1 year ago