Answer:
The air pressure in the ears increases
The volume of air in the ears increases
The change in volume causes discomfort
It takes time for the ears to dispell excess air past the ear drum.
Explanation:
As the plane engages in a steep incline into the atmosphere, the outside atmospheric pressure decreases with altitude. The air pressure in the ear, therefore, become greater than atmospheric pressure. The air volume in the ear therefore grows and pushes on the ear causing discomfort. As the air in the cabin pressurizes the discomfort eases away as pressure equalization is restored relative to the ear.
Answer:
C. 4x10⁻⁴ mol / (Ls)
Explanation:
Based in the reaction:
5 H₂O₂(aq) + 2 MnO₄⁻(aq) + 6 H⁺(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 O₂(g)
2 moles of MnO₄⁻ disappears while 5 moles of O₂ appears.
If 5 moles appears in a rate of 1.0x10⁻³mol /(Ls), 2 moles will disappear:
2 moles ₓ (1.0x10⁻³mol /(Ls) / 5 moles) = <em>4x10⁻⁴ mol / (Ls)</em>
Right answer is:
C. 4x10⁻⁴ mol / (Ls)
For a substance to occupy one half of an open container with the atoms being able to slide past each other, the most likely phase of the substance would be liquid.
Atoms of gases would not occupy just one-half of an open container because atoms of gases will diffuse and spread out from an open container.
Atoms of solids are fixed about a particular position and will most likely not be able to slide past each other in an open container.
Only the atoms of liquid take the shapes of their containers and do not have the capacity to diffuse out ordinarily. They are also able to flow despite the closeness of the atoms and would occasionally slide past each other.
More on states of matter can be found here: brainly.com/question/9402776
Molarity is defined as number of moles of solute in 1 L of solution.
Here, 0.1025 g of Cu is reacted with 35 mL of HNO_{3} to produced Cu^{2+} ions.
The balanced reaction will be as follows:
Cu+3HNO_{3}\rightarrow Cu(NO_{3})_{2}+NO_{2}+H_{2}O
From the above reaction, 1 mole of Cu produces 1 mole of Cu^{2+}, convert the mass of Cu into number of moles as follows:
n=\frac{m}{M}
molar mass of Cu is 63.55 g/mol thus,
n=\frac{0.1025 g}{63.55 g/mol}=0.0016 mol
Now, total molarity of solution, after addition of water is 200 mL or 0.2 L can be calculated as follows:
M=\frac{n}{V}=\frac{0.0016 mol}{0.2 L}=0.008 mol/L=0.008 M
Thus, molarity of Cu^{2+} is 0.008 M.
