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ahrayia [7]
2 years ago
15

Draw the Lewis structure (including resonance structures) for diazomethane (CH2N2)(CH2N2). For each resonance structure, assign

formal charges to all atoms that have formal charge.

Chemistry
1 answer:
Tanya [424]2 years ago
8 0

Answer : The Lewis-dot structure and resonating structure of CH_2N_2 is shown below.

Explanation :

Resonance structure : Resonance structure is an alternating method or way of drawing a Lewis-dot structure for a compound.

Resonance structure is defined as any of two or more possible structures of the compound. These structures have the identical geometry but have different arrangements of the paired electrons. Thus, we can say that the resonating structure are just the way of representing the same molecule.

First we have to determine the Lewis-dot structure of CH_2N_2.

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, CH_2N_2

As we know that carbon has '4' valence electrons, nitrogen has '5' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in CH_2N_2 = 4 + 2(1) + 2(5) = 16

Now we have to determine the formal charge for each atom.

Formula for formal charge :

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

For structure 1 :

\text{Formal charge on H}=1-0-\frac{2}{2}=0

\text{Formal charge on H}=1-0-\frac{2}{2}=0

\text{Formal charge on C}=4-2-\frac{6}{2}=-1

For structure 2 :

\text{Formal charge on H}=1-0-\frac{2}{2}=0

\text{Formal charge on H}=1-0-\frac{2}{2}=0

\text{Formal charge on C}=4-0-\frac{8}{2}=0

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Answer:

0.3229 M HBr(aq)

0.08436M H₂SO₄(aq)

Explanation:

<em>Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown concentration HBr(aq) required 18.45 mL of 0.3500 M NaOH(aq) to neutralize it, to the point where thymol blue indicator changed from pale yellow to very pale blue. Calculate the concentration (molarity) of Stu's HBr(aq) sample.</em>

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Let's consider the balanced equation for the reaction between HBr(aq) and NaOH(aq).

NaOH(aq) + HBr(aq) ⇄ NaBr(aq) + H₂O(l)

When the neutralization is complete, all the HBr present reacts with NaOH in a 1:1 molar ratio.

18.45 \times 10^{-3} L NaOH.\frac{0.3500molNaOH}{1LNaOH} .\frac{1molHBr}{1molNaOH} .\frac{1}{20.00 \times 10^{-3} LHBr} =\frac{0.3229molHBr}{1LHBr} =0.3229M

<em>Kemmi Major also does a titration. She measures 25.00 mL of unknown concentration H₂SO₄(aq) and titrates it with 0.1000 M NaOH(aq). When she has added 42.18 mL of the base, her phenolphthalein indicator turns light pink. What is the concentration (molarity) of Kemmi's H₂SO₄(aq) sample?</em>

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Let's consider the balanced equation for the reaction between H₂SO₄(aq) and NaOH(aq).

2 NaOH(aq) + H₂SO₄(aq) ⇄ Na₂SO₄(aq) + 2 H₂O(l)

When the neutralization is complete, all the H₂SO₄ present reacts with NaOH in a 1:2 molar ratio.

42.18 \times 10^{-3} LNaOH.\frac{0.1000molNaOH}{1LNaOH} .\frac{1molH_{2}SO_{4}}{2molNaOH} .\frac{1}{25.00\times 10^{-3}LH_{2}SO_{4}} =\frac{0.08436molH_{2}SO_{4}}{1LH_{2}SO_{4}} =0.08436M

6 0
2 years ago
Consider the following reaction (X = Cl or Br) which statement s is are correct?
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Explain why calcium combines in a different ratio to a fluoride ion versus an oxide ion.
jok3333 [9.3K]

Answer:

This is due the different charges of fluoride and oxide ions.

Explanation:

When calcium reacts it is oxidized to Ca²⁺. In the same way, fluoride ion is reduced to F⁻ and oxide ion to O²⁻.

When these ions are combined, the molecule must be neutral. That means 2 ions of F⁻ are necessaries and just 1 O²⁻ ion will reacts producing:

CaF₂ and CaO.

The different charges of these ions is the reason why calcium will combine in different ratios.

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A cylinder at left with balls evenly spaced throughout the cylinder has an arrow leading to a cylinder at right cylinder with ba
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gas to liquid

Explanation:

The change of state indicated by this analogy is from gas to liquid.

Cylinder to the left is filled with gases

Cylinder to the right is made up of liquid.

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  • Liquids have definite volume and flow with one another.
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7 0
2 years ago
Read 2 more answers
568 cm3 of chlorine at 25° C will occupy what volume at -25° C while the pressure remains constant?
Vsevolod [243]

Answer:

474.3 cm³

Explanation:

Given data:

Initial volume of chlorine gas = 568 cm³

Initial temperature = 25°C

Final volume = ?

Final temperature =  -25°C

Solution:

Initial temperature = 25°C (25+273 = 297 K)

Final temperature =  -25°C (-25 +273 = 248 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 568 cm³ × 248 K /297 K

V₂ = 140864 cm³.K / 297 K

V₂ = 474.3 cm³

6 0
2 years ago
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