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Ede4ka [16]
1 year ago
9

2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3H2(g)a. Determine the volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of

aluminum to produce aluminum sulfate.b. Determine the % yield if 112 g of aluminum sulfate is produced under the above conditions.
Chemistry
1 answer:
Ira Lisetskai [31]1 year ago
6 0

Answer:

a. 167 mL.

b. 39.3 %.

Explanation:

Hello!

In this case, for the undergoing chemical reaction, since 45.0 g of aluminum react, based on the 2:3 mole ratio with sulfuric acid, we can compute the required moles  as shown below:

n_{H_2SO_4}=45.0gAl*\frac{1molAl}{27.0gAl} *\frac{3molH_2SO_4}{2molAl} =2.50molH_2SO_4

Next, since the molarity of a solution is computed based on the moles and volume (M=n/V), we can compute the required volume of sulfuric acid as shown below:

V=\frac{n}{M}=\frac{2.50mol}{15.0mol/L}=0.167L

That in mL is 167 mL.

Moreover, for the percent yield, we compute the grams of aluminum sulfate that are produced based on the required 2.50 moles of sulfuric acid:

m_{Al_2(SO_4)_3}=2.50molH_2SO_4*\frac{1molAl_2(SO_4)_3}{3molH_2SO_4}*\frac{342.15gAl_2(SO_4)_3}{1molAl_2(SO_4)_3} \\\\m_{Al_2(SO_4)_3}=285.13gAl_2(SO_4)_3

Therefore the percent yield is:

Y=\frac{112g}{285.13g}*100\%\\\\Y=39.3\%

Best regards!

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Answer:

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Explanation:

<u>1. Number of moles of gasoline</u>

a)  Convert 60.0 liters to grams

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  • density = mass / volume
  • mass = density × volume
  • mass = 0.77kg/liter × 60.0 liter = 46.2 kg

  • 46.2kg × 1,000g/kg = 46,200g

b) Convert 46,200 grams to moles

  • molar mass of C₈H₁₈ = 114.2 g/mol
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  • number of moles = 46,200g / (114.2 gmol) = 404.55 mol

<u>2. Number of moles of carbon dioxide, CO₂ produced</u>

a) Balanced chemical equation (given):

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b) mole ratio:

  • 1 mol C₈H₁₈ / 8 mol CO₂ = 404.55 mol C₈H₁₈ / x

Solve for x:

  • x = 404.55mol C₈H₁₈ × 8 mol CO₂ / 1mol C₈H₁₈ = 3,236.4 mol CO₂

<u> 3. Convert the number of moles of carbon dioxide to volume</u>

Use the ideal gas equation:

  • pV = nRT
  • V = nRT/p
  • p = 1 atm
  • T = 298.15K
  • n = 3,236.4 mol
  • R = 0.08206 (mol . liter)/ (K . mol)

Substitute and compute:

  • V =3,236.4 mol × 0.08206 (mol . liter) / (K . mol) 298.15K / 1 atm
  • V = 79,183 liter

Round to two significant figures (because the density has two significant figures): 79,000 liters ← answer

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2 years ago
4. Which statement gives you enough information to say that the atom is electrically neutral?
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If the proton amd electron of atoms are equal it is said to be electrically nuetral

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2 years ago
A gas effuses 1.55 times faster than propane (C3H8)at the
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Answer:  The mass of the gas is 18.3 g/mol.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{Rate_{X}}{Rate_{C_3H_8}}=1.55

\frac{Rate_{X}}{Rate_{C_3H_8}}=\sqrt{\frac{M_{C_3H_8}}{M_{X}}}

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5 0
2 years ago
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Answer:

E. CH₄ < CH₃Cl < CH₃OH < RbCl

Explanation:

The molecule with the stronger intermolecular forces will have the higher boiling point.

The order of strength of intermolecular forces (strongest first) is

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RbCl is a compound of a metal and a nonmetal. It is an ionic compound, so it has the highest boiling point.

CH₃Cl has a C-Cl polar covalent bond. It has dipole-dipole forces, so it has the second lowest boiling point.

CH₃OH has an O-H bond. It has hydrogen bonding, so it has the second highest boiling point.

CH₄ has nonpolar covalent C-H bonds. It has only nonpolar bonds, so the only attractive forces are London dispersion forces. It has the lowest boiling point.

Thus, the order of increasing boiling points is

CH₄ < CH₃Cl < CH₃OH < RbCl

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mass sln = 750.0 g = mass solute + mass solvent

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⇒ mb = mol solute/Kg solvent (nb/wa)

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∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

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⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
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